600 kVAR, 12470V Capacitor...How to size overcurrent and conductors

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Hello,

I have a project where I am replacing a 4160V 600kVAR capacitor with a 12470V 600kVAR capacitor. Per NEC 460 I am coming up with 37.5A (600000/(12470*1.73) * 1.35).

Am I correct in using a #8, 15kV conductor?
 
Your amp calc appears correct but it might be difficult finding a #8 awg 15 kV conductor that will work. Minimum size is usually #2 awg for 15 kV shielded cable.

Fusing of capacitor banks has some nuances. I recommend you check with the manufacturer.
 
Hello,

I have a project where I am replacing a 4160V 600kVAR capacitor with a 12470V 600kVAR capacitor.

The "replacing" needs some clarification.

Are you actually going to apply 12470V instead of 4160 to the capacitor? Or will the applied voltage still be 4160?
The current flowing through the capacitor will be proportional to both the capacitance and the applied voltage.

A 12470V 600KVAR capacitor if used at 4160 volts will still have the same capacitance as when used at 12470V, and will therefore become a 600KVAR/9 = 67KVAR capacitor, and will draw 1/3 of the current that it would when used at 12470V. Since the capacitance will be smaller than for the original capacitor, the current will also be just 1/9 of the original current.

If you are moving the PF correction from the 4160 side of a transformer to the 12470 side of the transformer, then your calculations are correct.
 
The "replacing" needs some clarification.

Are you actually going to apply 12470V instead of 4160 to the capacitor? Or will the applied voltage still be 4160?
The current flowing through the capacitor will be proportional to both the capacitance and the applied voltage.

A 12470V 600KVAR capacitor if used at 4160 volts will still have the same capacitance as when used at 12470V, and will therefore become a 600KVAR/9 = 67KVAR capacitor, and will draw 1/3 of the current that it would when used at 12470V. Since the capacitance will be smaller than for the original capacitor, the current will also be just 1/9 of the original current.

If you are moving the PF correction from the 4160 side of a transformer to the 12470 side of the transformer, then your calculations are correct.

We are upgrading the campus loop from 4160 to 12470 so we are replacing the capacitor and a variety of pad mounted oil transformers.
 
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