advansed conduit bending

[dennisgontcharov]

hello gentelmen have a question on mr. richard a cox electircians guide to conduit bending book. in chapter 9 " four bend saddles" at the top of the page 39 example 1. he writes " Locate bend mark A. Height (8") plus 45* ?CONSTANT (5")? subtracted from distance (32") 8"+5"=13 "
my question is on this ?CONSTANT? which in this exanple is 5" for some rison. he isnt giving any explontaion before this or following this example about the constan. what if ur bending at a 30* angle offsets for the sadle. DOES THE CONSTANT STAY THE SAME OR IS IT DIFFERENT FOR EACH INDIVIDUAL SETS OF ANGLES LIKE A CONSTANT FOR A MULTEPLIER TO DITERMIN THE SPACE BETWEEN THE BENDS FOR A REQULAR OFFSETS. the rison im askin is as i mentiond before he isnt explaning about it at all in the chapter nor in the latter ones or the privious ones. please let me know if i can give you more info if my question isnt clear. thank you in advance
dennis:smile:

 

[barbeer]

Would this not be the take-up for 1/2 inch conduit? 6" for 3/4 etc.......?

 

[76nemo]

To heck with always using trig.. Make it easier on yourself and check out the Benfield technique. Jack Benfield that is:wink:

 

[480sparky]

Would this not be the take-up for 1/2 inch conduit? 6" for 3/4 etc.......?

That's my first thought. It's another word for take-up.

But I've never seen the book, let alone can follow what the OP is saying.

 

[electricalperson]

To heck with always using trig.. Make it easier on yourself and check out the Benfield technique. Jack Benfield that is:wink:

i use his method and it works pretty well. i dont bend emt every day but using his technique makes it easier. the trig method works just as good but using the bendfield technique eliminates all of the fancy formulas

 

[peter d]

the trig method works just as good but using the bendfield technique eliminates all of the fancy formulas

The funny thing is that the "Benfield method" is based on trigonometry.

 

[cripple]

advansed conduit bending

Only constant I?m aware of that could apply is the shrinkage constant per degree for each inch of offset, which is .0083 x the degrees x the total offset in inches.
Shrinkage = degrees x 0.0083 x offset in inches
Shrinkage = 450 x .0083 x 8
Shrinkage = 3735 x 8
Shrinkage = 2.988 round up 3

 

[mistermudd]

I am pretty sure you are referring to the constant that you would add to a measurement so that center of the bend ends up where you want it. You can find the constant for a certain size pipe & angle on a particular bender by bending a scrap piece of pipe. Mark the pipe, put the mark on the arrow or front of shoe (I can't remember) and bend the pipe to the angle you want. Find the center of the bend by using a straight edge held against the side of the pipe twice marking an X on the center of the bend. Measure from the mark to the X.

 

[Minuteman]

I looked on my bookshelf, and I have the second edition of "ELECTRICIANS GUIDE TO CONDUIT BENDING' Copyright 1982. Here is page 39.

Barbeer is right, the 5" constant that you are asking about is the 1/2" conduit take up. On a Benfield there is a 5" radius of the bending shoe. Hope this helps.