Another Wa State Admin Test Doozy
- Thread starter pipeit
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bphgravity
Senior Member
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- Florida
Re: Another Wa State Admin Test Doozy
40 x 1000 x 3 = 120,000
40 x 1500 x 2 = 120,000
Total light = 240,000
First 3000 = 3,000
Next 117,000 @ 35% = 40,950
Remainder 120,000 @ 25% = 30,000
Total Demand = 73,950
Range Column C = 15,0000 + 40,000 = 55,000
Range Column B = 320,000 x 22% = 70,400
Appliances = 2,500 x 40 = 100,000
1,200 x 40 = 48,000
600 x 40 = 24,000
Total Appliance = 172,000
A/C = 18 x 120 x 40 = 86,400
Total Load = 73,950 + 55,000 + 172,000 + 86,400 = 387,350 / 240 = 1,614-amperes
My answer is E, none of the above?
[ March 07, 2005, 07:41 PM: Message edited by: bphgravity ]
40 x 1000 x 3 = 120,000
40 x 1500 x 2 = 120,000
Total light = 240,000
First 3000 = 3,000
Next 117,000 @ 35% = 40,950
Remainder 120,000 @ 25% = 30,000
Total Demand = 73,950
Range Column C = 15,0000 + 40,000 = 55,000
Range Column B = 320,000 x 22% = 70,400
Appliances = 2,500 x 40 = 100,000
1,200 x 40 = 48,000
600 x 40 = 24,000
Total Appliance = 172,000
A/C = 18 x 120 x 40 = 86,400
Total Load = 73,950 + 55,000 + 172,000 + 86,400 = 387,350 / 240 = 1,614-amperes
My answer is E, none of the above?
[ March 07, 2005, 07:41 PM: Message edited by: bphgravity ]
Re: Another Wa State Admin Test Doozy
Bryan in your calculation you forgot to derate appliance load by 75%.when you recalculate with 129,000va for appliances you end up with 344,350 total va /240=1434.79 or 1435 amps. by the way thanks for showing your math because i was not taking into account column c of table 220.19 at all and i have a funny feeling that may be part of my problem finding the right answer.thanks so much!
[ March 07, 2005, 09:47 PM: Message edited by: pipeit ]
Bryan in your calculation you forgot to derate appliance load by 75%.when you recalculate with 129,000va for appliances you end up with 344,350 total va /240=1434.79 or 1435 amps. by the way thanks for showing your math because i was not taking into account column c of table 220.19 at all and i have a funny feeling that may be part of my problem finding the right answer.thanks so much!
[ March 07, 2005, 09:47 PM: Message edited by: pipeit ]
bphgravity
Senior Member
- Location
- Florida
Re: Another Wa State Admin Test Doozy
I don't see how you can apply a demand factor to the appliance load. You don't have four of them?
I don't see how you can apply a demand factor to the appliance load. You don't have four of them?
Re: Another Wa State Admin Test Doozy
73,950--> General lighting
55,000--> Range
129,000-> 0.75% Appliances: art. 220.53
86,400--> A/C
-----------
344,350 divided by 240= 1434.79
(A) 1435 amperes
[ March 08, 2005, 06:38 AM: Message edited by: dillon3c ]
------>220.53:Appliance demand factor of 75% would apply to this question...
73,950--> General lighting
55,000--> Range
129,000-> 0.75% Appliances: art. 220.53
86,400--> A/C
-----------
344,350 divided by 240= 1434.79
(A) 1435 amperes
[ March 08, 2005, 06:38 AM: Message edited by: dillon3c ]
bphgravity
Senior Member
- Location
- Florida
Re: Another Wa State Admin Test Doozy
Thanks, I was only looking at per unit instead of total on one service... By the way, I know this is for exam preparation but this exact question proves the point that a standard and optional method are unecessary and shoul dbe consolidated to jusr one method.
Per 220.84, the connected load is 818,400 va.
818,400 x 28% = 229,152 / 240 = 955-amperes.
Why would anyone want to use the standard method? The standard method took me about 6 minutes to calculate, and I still screwed it up becausde of all the demands factors permitted for every separate load. This makes no sense. The Optional method took all of 1 minute and its easy. Find the connected load, apply the demand, your done.
Thanks, I was only looking at per unit instead of total on one service... By the way, I know this is for exam preparation but this exact question proves the point that a standard and optional method are unecessary and shoul dbe consolidated to jusr one method.
Per 220.84, the connected load is 818,400 va.
818,400 x 28% = 229,152 / 240 = 955-amperes.
Why would anyone want to use the standard method? The standard method took me about 6 minutes to calculate, and I still screwed it up becausde of all the demands factors permitted for every separate load. This makes no sense. The Optional method took all of 1 minute and its easy. Find the connected load, apply the demand, your done.
Re: Another Wa State Admin Test Doozy
-->A Question for the Electrical Instructors out there of this form.
In my above calculation of the Fixed Motor Rated Appliances useing the -(Standard Method)- of Article 220.
Does any of the Instructors out there see anything,or one step missing in my tabulation of this fixed Motor Appliance Calculation..I have returned to classes, and the way it's being taught this calculation would be incomplete.--If my Instructor is correct,then the true answer of this question in Standard Method, is in fact not posted above.And in the WA.State Exam Question,would be wrong..
-Want some Instructor feedback,in catching this error...
----- dillon ----
-->A Question for the Electrical Instructors out there of this form.
In my above calculation of the Fixed Motor Rated Appliances useing the -(Standard Method)- of Article 220.
Does any of the Instructors out there see anything,or one step missing in my tabulation of this fixed Motor Appliance Calculation..I have returned to classes, and the way it's being taught this calculation would be incomplete.--If my Instructor is correct,then the true answer of this question in Standard Method, is in fact not posted above.And in the WA.State Exam Question,would be wrong..
-Want some Instructor feedback,in catching this error...
----- dillon ----
Re: Another Wa State Admin Test Doozy
I would also be interested in an answer from an instructor as I have worked this same question out and every time came up with 1435 amps per the standard method. Problem is that the State of Washington people who came up with this "new" system of theirs will not let you know what you missed on a test or what you had right. They are also people who do not sign the front side of a paycheck, keep that in mind.
I would also be interested in an answer from an instructor as I have worked this same question out and every time came up with 1435 amps per the standard method. Problem is that the State of Washington people who came up with this "new" system of theirs will not let you know what you missed on a test or what you had right. They are also people who do not sign the front side of a paycheck, keep that in mind.
Re: Another Wa State Admin Test Doozy
I hard to imagine that a testing facillity/ state exam author does not offer, via payment for reimbursement of their time to view the test taken in way of incorrect answers on test.In N.Carolina, the option is offered,via a appointment scheduled and a fee.
snapco,
I hard to imagine that a testing facillity/ state exam author does not offer, via payment for reimbursement of their time to view the test taken in way of incorrect answers on test.In N.Carolina, the option is offered,via a appointment scheduled and a fee.
Re: Another Wa State Admin Test Doozy
This question has been on the table for some time.The problem that I see with this question is on the fixed motor rated appliances.In Wa.State exam for Standard Calculation,needing to applying 220.18(a),doesn't fit into their equation in above multible answers.Correct answer is in fact 1435.72=>1436 amperes
This test question is one ampere shy of correct answer on my calculator.
This question has been on the table for some time.The problem that I see with this question is on the fixed motor rated appliances.In Wa.State exam for Standard Calculation,needing to applying 220.18(a),doesn't fit into their equation in above multible answers.Correct answer is in fact 1435.72=>1436 amperes
This test question is one ampere shy of correct answer on my calculator.
resistance
Senior Member
- Location
- WA
Re: Another Wa State Admin Test Doozy
I got 1572amps.
I got 1572amps.
resistance
Senior Member
- Location
- WA
Re: Another Wa State Admin Test Doozy
to add: We should do something about this! I'm willing to sign my name on any documentation needed to stop this assumed fraud. It's strange that no one can get the correct answer!?
If someone knows the solution, then come forward.
Thanks!
Also, thanks to the people who are postinf answers and questions. This is giving people the opportunity to practice. I've been gathering the questions and working the problems. Yet, I'm on the same boat as most of us.
A=1435 ,B=1596, C=1755 ,D=1950
1000(3)(40)=120000
1500(2)(40)=120000
1500(40) added, because the question said no laundry, but did not say no laundry for ea unit=60000
Total=300000
-3000@ 100%=3000
Remaining 297000 @.35=103950+3000=106950
Range= 55,000 T220.19
H20=100,000(.75)=75000
Dispo=48000(.75)=36000
Dish=24000(.75)=18000
AC 86,400
Total= 270400+106950=377350/240=1572.29 --which doesn't show as an answer
[ March 25, 2005, 07:41 PM: Message edited by: resistance ]
to add: We should do something about this! I'm willing to sign my name on any documentation needed to stop this assumed fraud. It's strange that no one can get the correct answer!?
If someone knows the solution, then come forward.
Thanks!
Also, thanks to the people who are postinf answers and questions. This is giving people the opportunity to practice. I've been gathering the questions and working the problems. Yet, I'm on the same boat as most of us.
A=1435 ,B=1596, C=1755 ,D=1950
1000(3)(40)=120000
1500(2)(40)=120000
1500(40) added, because the question said no laundry, but did not say no laundry for ea unit=60000
Total=300000
-3000@ 100%=3000
Remaining 297000 @.35=103950+3000=106950
Range= 55,000 T220.19
H20=100,000(.75)=75000
Dispo=48000(.75)=36000
Dish=24000(.75)=18000
AC 86,400
Total= 270400+106950=377350/240=1572.29 --which doesn't show as an answer
[ March 25, 2005, 07:41 PM: Message edited by: resistance ]
resistance
Senior Member
- Location
- WA
Re: Another Wa State Admin Test Doozy
Ok I see where I went wrong. Yet Dillon and bph-how did you guys get to 73950 for the general lighting load? I can see that you did this:
240000-3000=237000
then you took 117,000@.35
and 120,000@.25 (T220.11)
but how did you come to getting 117000 and 120000???
I also found that adding in the laundry was a mis-read on my half.
Hope to hear from you! Thanks!
Ok I see where I went wrong. Yet Dillon and bph-how did you guys get to 73950 for the general lighting load? I can see that you did this:
240000-3000=237000
then you took 117,000@.35
and 120,000@.25 (T220.11)
but how did you come to getting 117000 and 120000???
I also found that adding in the laundry was a mis-read on my half.
Hope to hear from you! Thanks!
resistance
Senior Member
- Location
- WA
Re: Another Wa State Admin Test Doozy
Thanks Dillion!
I see Dillions got this calculation stuff down!
Thanks to all!
Thanks Dillion!
I see Dillions got this calculation stuff down!
Thanks to all!
resistance
Senior Member
- Location
- WA
Re: Another Wa State Admin Test Doozy
Thanks for the help!
[ April 18, 2005, 02:06 AM: Message edited by: resistance ]
Thanks for the help!
[ April 18, 2005, 02:06 AM: Message edited by: resistance ]
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