Dale lee
Member
- Location
- Fort myers Fl
- Occupation
- Electrician
Hey guys, in the process for the second time this week of trying to determine an adjustment factor for just motors serving multiple boat lifts
the specific setup is 13 boat slips with a 100 amp feeder to a dock panel, from the panel to each slip is a combination of 20 and 30 amp branch circuits. each slip is a 2 motor boat lift, there is no pedestal.
currently i have been denied by permitting department essentially for not having a load calculation for an existing system. i was contracted to replace 2 sub panels at the dock and condense them into one panel.
no while I'm not sure why I'm required to do this I am attempting anyway, mostly to figure out the load calc question.
so heres the facts-
100A feeder
13 slips with 2- 3/4 hp motor(s) @ 240V per lift, worst case you can assume 2 or three could be used at the exact same time and and 3 min (being generous)
555.6 demand factors only apply to shore power receptacles
430.24 says 125% flc of highest rated motor plus sum of 100% flc for remaining motors
430.26 say ahj can grant permission for feeder to have less ampacity than specified in 430.24 if all motors aren't operating at 1 time
430.248- 3/4 hp motor @ 230V = 6.9A each
125% largest fla= 8.625, sum of (25) remaining motors @ 6.9= 172.5+ 8.625= 181.125
I've been told that other guys have used the motor as a outlet and then used 555.6 but that doesnt make sense
any help would be appreciated as i think its absurd to tell customer their panel change is gonna cost 15,000 (no its not easy to upsize the feeders)
the specific setup is 13 boat slips with a 100 amp feeder to a dock panel, from the panel to each slip is a combination of 20 and 30 amp branch circuits. each slip is a 2 motor boat lift, there is no pedestal.
currently i have been denied by permitting department essentially for not having a load calculation for an existing system. i was contracted to replace 2 sub panels at the dock and condense them into one panel.
no while I'm not sure why I'm required to do this I am attempting anyway, mostly to figure out the load calc question.
so heres the facts-
100A feeder
13 slips with 2- 3/4 hp motor(s) @ 240V per lift, worst case you can assume 2 or three could be used at the exact same time and and 3 min (being generous)
555.6 demand factors only apply to shore power receptacles
430.24 says 125% flc of highest rated motor plus sum of 100% flc for remaining motors
430.26 say ahj can grant permission for feeder to have less ampacity than specified in 430.24 if all motors aren't operating at 1 time
430.248- 3/4 hp motor @ 230V = 6.9A each
125% largest fla= 8.625, sum of (25) remaining motors @ 6.9= 172.5+ 8.625= 181.125
I've been told that other guys have used the motor as a outlet and then used 555.6 but that doesnt make sense
any help would be appreciated as i think its absurd to tell customer their panel change is gonna cost 15,000 (no its not easy to upsize the feeders)