sparkie001 said:
If he is installing 3 of them for one machine, they are most likey boost autoxfmrs. Otherwise they are step-up transformers.
The 3 neutral leads of the boost xfmrs that are tied together will carry FLA. The single conductor connection from them to the source neutral will carry unbalanced current, if any. Yes?
Hi, sparky.
On point one, I say No, they are not necessarily boost autotransformers, but even if they are, they would be single-winding devices with a voltage ratio equal to the turns tap ratio. Let's assume for the moment that you are right, and that the transformers are autotransformers.
If the bottom of the transformer is H4, as the OP has stated, and the "primary" tap is H2, then H1 would be the high side of the autotransformer, and connected to the load, per phase. In other words, each winding would consist of H4 at the bottom, H2 somewhere close to the top, and H1 slightly above that.
The primary circuit of the transformer, in that case, would be the connection between H2 and H4. Since there is no separate secondary winding, per se, then the virtual secondary of the transformer would be the section of winding between H4 (on the low side) and H1 (on the high side).
Take that connection and multiply the scenario times three for all three phases, and you end up with three single-winding autotransformers. They are connected as follows:
The supply-side connections of cores A, B and C, respectively, will be connected to H2 of each of the three cores. H4 of each core will be connected together to form the common supernode.
The "secondary" of the system will be derived by connecting to the "H1" terminals of each of the windings. If a neutral is needed, it will be made by connecting to the H4 supernode.
On your point two, I say Yes. That is exactly right. If I understand the application, the only current flowing on the primary "neutral" leg will be any imbalance in magnetization current for the three transformer cores, whether they be single or double winding devices.
One of these days I'll figure out how to draw a schematic and post it to this forum. That would make it so much easier to 'splain what I'm trying to say.
Am I making sense, or would you like me to take another run at it?
BigBillEQ, I offer
this as an explanation of a supernode. In this instance, the supernode also works as the reference node.
regards,
Dan