Code
Code
So if I am understanding You, You are saying that "if the connector being used does not specifically specify that it is for this purpose, then that is the reason for it not being "legal" or code compliant?" Would this be a UL listing or a manufactures description of the connector? I am not arguing Your reply, I just want to completely understand how an inspector would justify this as a violation.
This would a code violation
This question refers to Artilcle, 110.3 b Instalallation and Use, as well as article 300 wiring method (300.4.300.13,300.15,310.15,334.30 and 334.80
in a nut shell there are no 2 inch conector listed for multi cable use such as you refer to (please see the" U.L. white book" and manufactures listing).If the conector is not listed for the specific use then it would be a code violation and if the conductors are grouped or bundle for more than 24 inches(such as in a conduit or stapled together) they must be derated according to 334.80 for NM type ("Romex"),and 310.15
Here is an example
The basic formula for Conductor Ampacity would be as follows:
(Table Value@T310.16) ?(Correction@bottom of t310.16 )?(Adjustment Factor@31.15 (b)(2)(a))
Must read 110.14c
Example:
there are (7) #8 AWG THWN single copper conductors are to be installed in a 1 1/2" aluminum conduit. All conductors are current carrying conductors. What is the allowable ampacity of each conductor? Assume the ambient temperature is 95 degrees F. Assume 60 degree C terminations.
Step 1: Go to Table 310.16 Look at the Table value for a #8 THWN conductor.
Table Value equals 55 amps for a #8 THWN conductor.
Step 2: Go to the bottom of Table 310.16 for your Ambient Temperature Corrections.
Corrections Table Value for 95 degrees F is 0.96 (multiplier)
Step 3: Go to Table 310.15(b) (2) (a)
For 7 current carrying conductors the Adjustment factor is 70%
Step 4: Multiply Step 1 and Step 2
55amps x 0.96 = 52.8 amps
Step 5: Multiply the sum of Step 1 and 2 by Step 3
Multiple 52.8 amps x 70% = 52.8 x 0.70 = 36.96 amps
Therefore, the maximum ampacity of these #8 THWN conductors would be 36.96 amps.
55 x 0.96 x 0.70 = 36.96 amps
please see example in the NFPA 70, 2008 N.E.C Hand book for an example