Re: Breakers protecting generators, false protection?
The intent of the question is if "generator protection" is really understood. What is commonly misunderstood is what does it take to trip a breaker.
Simply for example, a breaker that is rated 2000a has a specific inverse time current trip current curve, I2t. Does the generator have the capabiltity of producing enough overcurrent, that is current abouve 2000a, for a long enough period of time in order to trip the breaker? I do have a file of trip curves on file but for simplification will use NEMA AB4 Guidelines for Inspection and Maintenance of Molded Case Circit Breakers Used in Commercial and Industrial Applications as a basis to illustrate my example. Table 5-3 is a table of values for inverse time trip tests at 300% of the rated continuous current of circuit breakers. breakers with a range of rated continuous current amperes 10 1601-2000a should trip in less than 800 seconds. That's over 13 minute! Can a generated with a rated continuous output of 2000a generate 6000a for up to 13 minutes without damage?? Also, just how much fault current will the generator be able to provide into a bolted fault? Breaker commonly have a instantaneous of magnetic pickup range of between 5 and 10x the rating of the breaker. In the case of a 2000a rated breaker that's between 10,000 and 20,000 amps.
This reflects the "Set point" of the commonly available inductrial breaker. Unless there are set points available that are more in line with the currents that would be damaging to a generator there may be not real protection.
However, there are some specially calibrated breakers that are available from some manufactures.