I have just found your forum from a Google search on Buck / Boost transformers. I have had experience of using them to provide 230V from 208V but now I need to use one to buck 277V to 230V.
When boosting the voltage I from say 200V to 250V I understand that the power provided by the 50V winding is supplied by the 200V winding and increases the 200V supply current by the transformer ratio, so for a 100A load the primary must pull 50/200 x 100 = 25 A so the supply current is 100+25 = 125A IE 25kVA. I am also ok that the transformer rating need only be 50 x 100 VA = 5kVA. However, when bucking the voltage (down) I get a little confused!
Taking my example above I now have a 250V supply and need to supply a 200V 100A (different) load IE 20kVA. With a supply of 250V the current should be around 20K/250 = 80A.
The 50V winding will be wired to reduce the voltage to my load by 50V ? ok, but how does it reduce the current from 100A to 80A? I guess the
200V winding is now supplying some power to the load.
Working backwards I assume the 50V winding is passing only the 80A so in this example the transformer is 4kVA. Now 4K @ 200V is 20A so it looks like the 200V winding is providing 20A of the load. However I do feel I started with the answer and worked backwards!
Does anyone know the correct way to size a buck transformer??
Graham
When boosting the voltage I from say 200V to 250V I understand that the power provided by the 50V winding is supplied by the 200V winding and increases the 200V supply current by the transformer ratio, so for a 100A load the primary must pull 50/200 x 100 = 25 A so the supply current is 100+25 = 125A IE 25kVA. I am also ok that the transformer rating need only be 50 x 100 VA = 5kVA. However, when bucking the voltage (down) I get a little confused!
Taking my example above I now have a 250V supply and need to supply a 200V 100A (different) load IE 20kVA. With a supply of 250V the current should be around 20K/250 = 80A.
The 50V winding will be wired to reduce the voltage to my load by 50V ? ok, but how does it reduce the current from 100A to 80A? I guess the
200V winding is now supplying some power to the load.
Working backwards I assume the 50V winding is passing only the 80A so in this example the transformer is 4kVA. Now 4K @ 200V is 20A so it looks like the 200V winding is providing 20A of the load. However I do feel I started with the answer and worked backwards!
Does anyone know the correct way to size a buck transformer??
Graham
