Wiggy333
New member
- Location
- Greater Los Angeles Area
For some reason, I'm blocked on this. I need to know the minimum branch-circuit overcurrent protection for a single cabinet-mounted oven with a nameplate rating of 8kW/230 volts.
As near as I can figure using Table 220.19 Note 4 and some basic calculations. 8000/230 = 34.7 amperes, the minimum wire size would be #8 AWG copper (50 Amps)and the overcurrent device would be 40 amperes.
Based on the restrictions of 240.4(D) on #10 AWG (30 amps O/C) and the requirements of Table 210.24 and the language of 210.23 (B) and (C) this seems logical.
Do I now have to use the Demand Factors in Column B of Table 220.19 as noted in Note 3?
8000 x 80% = 6400/230 = 27.8 amp which would allow #10 AWG/30 amp O/C.
As near as I can figure using Table 220.19 Note 4 and some basic calculations. 8000/230 = 34.7 amperes, the minimum wire size would be #8 AWG copper (50 Amps)and the overcurrent device would be 40 amperes.
Based on the restrictions of 240.4(D) on #10 AWG (30 amps O/C) and the requirements of Table 210.24 and the language of 210.23 (B) and (C) this seems logical.
Do I now have to use the Demand Factors in Column B of Table 220.19 as noted in Note 3?
8000 x 80% = 6400/230 = 27.8 amp which would allow #10 AWG/30 amp O/C.