If 30 degree offset has 1/4" shrink per inch of bend. The table for shink for 6 inch offset, will be 1 1/2 inches of shrink. From this [(1 ? cos θ) ? 1] ? sin θ
you came up with 1.856
But now you are taking gain into account. I do not understand why you do this. I guess your'e saying that the raduis of be bends has a effect on the shrink calculation
The values posted by nunu161 are approximate shrink per inch of offset. They will serve the purpose in many if not most instances, especially those where you can fudge the angle a little, and/or cut the tail to length after bending.
And yes, the radius of the bends have an effect on shrink... and it actually has an affect on bend to bend distance also. Most reference materials only account for straight line measurement. A bend in the "corners" will always shortcut that distance a little. It is called
gain, and is more notably discussed for 90? bends in reference material. However, all bends have some gain... varying in length from negligible to inescapable (i.e. where pre-bend accuracy is required).
Do yourself a favor and get one of these...
http://www.howtowireahouse.com/Greenlee_38405.html
Check your supply house to see if they have it for free... but usually when they get them they disappear real fast, and usually on the who-buys-the-most buddy system
The method for calculating shrink in this hanbook is, IIRC, to find the cosecant of the bend angle and subtract the secant. I believe the result is the same as the formula I gave you (cosecant and secant are just inverted trigonometric functions). It also has a table of gain mulitpliers, amongst a bevy of other info... some related directly to their bending equipment, some not.