Calculating Heat Dissipation In Calories

Status
Not open for further replies.
physis

physis

Senior Member
Rattus wanted to come up with a nasty math question so I found one for him.

What amount of heat (in calories) is produced by a 10 ohm resistor carrying 0.3 amps for 3 minutes?
 
Re: Calculating Heat Dissipation In Calories

To be clear, I will use the more precise term ?kilogram-calories,? rather than the general conversational term "calories."
</font>
  • <font size="2" face="Verdana, Helvetica, sans-serif">10 ohms times 0.3 amps (squared) equals 0.9 watts (or 0.9 joules per second)</font>
<font size="2" face="Verdana, Helvetica, sans-serif"></font>
  • <font size="2" face="Verdana, Helvetica, sans-serif">0.9 joules per second times 3 minutes times 60 seconds (per minute) equals162 joules.</font>
<font size="2" face="Verdana, Helvetica, sans-serif"></font>
  • <font size="2" face="Verdana, Helvetica, sans-serif">162 joules times .0002389 kilogram-calories (per joule) equals .0387 kilogram-calories.</font>
<font size="2" face="Verdana, Helvetica, sans-serif">What?s the nasty part? :D
 
Re: Calculating Heat Dissipation In Calories

Well, you shouldn't be allowed Charlie. :D

An hour and a half though, for you, it must have been a good one! ;)

Your math's a little different than mine. When I get from work I'll put up my formula.
 
Re: Calculating Heat Dissipation In Calories

Originally posted by charlie b:
...
What?s the nasty part? :D
Click to expand...
Finding kilo-calories/joule :D

[ April 26, 2005, 04:44 PM: Message edited by: rbalex ]
 
Re: Calculating Heat Dissipation In Calories

Somehow Charlie, I'm envisioning five or six 12 pound text books open on your desk, beads of sweat pouring off your brow, piles of crumpled scratch paper spilling over the rim of the basket, and your secretary holding all calls. :D

Edit: I found the difference in our math. I have 4.19 joules/calorie instead calories/joule.

[ April 26, 2005, 09:28 PM: Message edited by: physis ]
 
Status
Not open for further replies.
Top