I am reading Conductor sizing (11-19-99) by Mike Holt. Free stuff section.
On page 2 1st problem, Step 3: while correcting ampacity for #4 THHN conductor, instead of using 66 amp multiplied by the correction factor )0.80, the ampacity taken from 90 degree C column of 310.16 and multiplied by the factor 0.80.
Same method is followed in the 2nd problem at Step 3 on the same page.
I do not find any section saying that we have to use ampacity of 90 degree C column. The coorection table at the bottom of the Table 310.16 does not say anything about it. It just said mutliply the factor with the above ampacity to obtain the correct ratings.
Please clarify. Thanks. Aftab
On page 2 1st problem, Step 3: while correcting ampacity for #4 THHN conductor, instead of using 66 amp multiplied by the correction factor )0.80, the ampacity taken from 90 degree C column of 310.16 and multiplied by the factor 0.80.
Same method is followed in the 2nd problem at Step 3 on the same page.
I do not find any section saying that we have to use ampacity of 90 degree C column. The coorection table at the bottom of the Table 310.16 does not say anything about it. It just said mutliply the factor with the above ampacity to obtain the correct ratings.
Please clarify. Thanks. Aftab