JasonMT
Member
- Location
- United States
Im trying to figure out the correct conduit size (schedual 40 PVC) to use with a 4 conductor cable. The cable contains 4 #6 XHHW-2 conductors. I know that Nec says: A multiconductor cable or flexible cord of two or more conductors shall be treated as a single conductor for calculating percentage conduit fill area. I measured the cable, It measures 5/8 of a inch, and is perfectly round. I used the formula, A= 3.14* R squared. Which comes out to be 1.23 inches squared. Chapter 9 tables tell me schedual 40 PVC with one wire 53%. So I used this column which I came out with 2 inch PVC= 1.744 In. Sq.. 1 1/2 = 1.052 In. Sq.. 1.23 In. Sq. is between these 2 numbers. So I should use 2 inch sch 40 PVC. Is This correct?
I also recently passed my state Journeyman test recently. I used this site for studying for the exam. I had alot of questions. That alot of people helped me with. I just want to say thank you for your help.
I also recently passed my state Journeyman test recently. I used this site for studying for the exam. I had alot of questions. That alot of people helped me with. I just want to say thank you for your help.