Conduit Fill

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augie47

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Location
Tennessee
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State Electrical Inspector (Retired)
Where am I making my mistake ?
Given 3" Sch 80 PVC and 600kcmil Cu.
I was asked how large a conductor I could add given 3 conductors in the conduit.
Table C9 shows 3 600 kcmils allowed in a 3" Sch 80 but when you go back and do the math using Chapter 9, (3) 600 kmil THWNs have a combined area of 2.6028 which exceeds the Table 4, over 2 wire, available area of 2.577.
 
Note 7 to the Chapter 9 Tables allows rounding up the allowable number of identical conductors when the first digit after the decimal place is 8 or 9. 2.577/0.8676 = 2.97, so it gets rounded up to 3.

Cheers, Wayne
 
That part gets everyone. When I was doing the tables for Annex C I had to come here and ask how to make my formula round up from .8 instead of .5 :D
 
Where am I making my mistake ?
Given 3" Sch 80 PVC and 600kcmil Cu.
I was asked how large a conductor I could add given 3 conductors in the conduit.
Table C9 shows 3 600 kcmils allowed in a 3" Sch 80 but when you go back and do the math using Chapter 9, (3) 600 kmil THWNs have a combined area of 2.6028 which exceeds the Table 4, over 2 wire, available area of 2.577.

By letting someone ask an old person to do math!:D
 
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