electrofelon
Senior Member
- Location
- Cherry Valley NY, Seattle, WA
I have this crimper (many other companies make/sell the same/similar thing):
www.milwaukeetool.com
I have the 840 W die with which I can crimp the blackburn "common die" lugs which go from #6 thru 350. With the fixed D and a w style O die I can do all Blackburn "WR" H taps in #6 thru 250. My local supply house stocks both of those connector series.
The only thing I feel I am missing, and have a need for coming up actually, is to be able to crimp lugs on 500 compact AL. It seems there must be a way to do this but I am confused. If you go here:
www.specialized.net
and scroll down to "Burndy W-dies for copper connectors" there is an "RT" series and a "VT" series. What is the difference? For the VT series, there is an asterisk next to the W34VT which seems to say it is limited to certain tools - I dont understand that. IF it is a W style seems like it should fit, or are they just thinking certain W style tools do not provide the force needed? Thanks.

Lineman's Crimper w/ Fixed BG

I have the 840 W die with which I can crimp the blackburn "common die" lugs which go from #6 thru 350. With the fixed D and a w style O die I can do all Blackburn "WR" H taps in #6 thru 250. My local supply house stocks both of those connector series.
The only thing I feel I am missing, and have a need for coming up actually, is to be able to crimp lugs on 500 compact AL. It seems there must be a way to do this but I am confused. If you go here:
Burndy U and W Dies – Burndy Die Chart
BURNDY dies are in stock and ready to ship from Specialized Products Company - as well as crimp tools, lugs and hydraulic cutters.

and scroll down to "Burndy W-dies for copper connectors" there is an "RT" series and a "VT" series. What is the difference? For the VT series, there is an asterisk next to the W34VT which seems to say it is limited to certain tools - I dont understand that. IF it is a W style seems like it should fit, or are they just thinking certain W style tools do not provide the force needed? Thanks.