Alwayslearningelec
Senior Member
- Location
- NJ
- Occupation
- Estimator
So after conductor ampacity adjustment/corrections for a continuous load you don't need to use 125% of the load but only a 100%?
Continuous Load
- Thread starter Alwayslearningelec
- Start date
- Location
- Connecticut
- Occupation
- Engineer
Yes, that's correct
Find the conductor size needed for 100% of the non-continuous load plus 125% of the continuous load (without any adjustments/corrections).
Then find the conductor size needed for 100% of the non-continuous load plus 100% of the continuous load, after any adjustments/corrections.
The larger size conductor is required.
Note, also, that the ampacity of the conductor after any adjustments/corrections must be properly protected per Art. 240.
Find the conductor size needed for 100% of the non-continuous load plus 125% of the continuous load (without any adjustments/corrections).
Then find the conductor size needed for 100% of the non-continuous load plus 100% of the continuous load, after any adjustments/corrections.
The larger size conductor is required.
Note, also, that the ampacity of the conductor after any adjustments/corrections must be properly protected per Art. 240.