brother
Senior Member
There's the new equipment with multimotors (3 of them) and a control center etc.. that is factory wired and the name plate only tells of the FLA, voltage, frequency, the hp of one of the motors. The manufacturer did not follow 2008 430.7(D) (1) that states they should tell YOU what the minimum supply circuit conductor ampacity and the maximum ampere rating of the circuit short-circuit and ground-fault protective device is.
The debate is about the minimum size conductors and size of the overloads (fuses) that should feed this equipment from the final disconnect to the equipment because the name plate on the equipment is 75 FLA total, and the circuit that was ran to it is 80 amps , #4 AWG 80 amp fuses. I believed that it should have the 75 fla X 1.25 =93.75 or 100 amp since we are not certain what the manufacturer did in getting to the FLA, did they or did they not accout for the 125% and what is the amp draw of all the other loads? Even if we did the 3 15 hp 460volt we get 21 X1.25 +21+21=68.25 just for the motors.
I know if it was not a 'factory wired' unit then we would just calculated with the 3 motors at 125% of the largest motor plus 100% of the other motors and the 100% of the other equipment IF we know what amps they pulled.
Called the manufacturer and they say they were not aware of 430.7(D) (1), so they weren't sure what to tell me !!
Ive read both 430.24 and 430.53 Branch circuits and still come up with my same answer to error on the side of caution.
Whats your opinion on this??
The debate is about the minimum size conductors and size of the overloads (fuses) that should feed this equipment from the final disconnect to the equipment because the name plate on the equipment is 75 FLA total, and the circuit that was ran to it is 80 amps , #4 AWG 80 amp fuses. I believed that it should have the 75 fla X 1.25 =93.75 or 100 amp since we are not certain what the manufacturer did in getting to the FLA, did they or did they not accout for the 125% and what is the amp draw of all the other loads? Even if we did the 3 15 hp 460volt we get 21 X1.25 +21+21=68.25 just for the motors.
I know if it was not a 'factory wired' unit then we would just calculated with the 3 motors at 125% of the largest motor plus 100% of the other motors and the 100% of the other equipment IF we know what amps they pulled.
Called the manufacturer and they say they were not aware of 430.7(D) (1), so they weren't sure what to tell me !!
Ive read both 430.24 and 430.53 Branch circuits and still come up with my same answer to error on the side of caution.
Whats your opinion on this??