Re: Derating conductors of one circuit
Originally posted by mhulbert: Charlie, Not sure I follow you.
It's probably me who is not following you. I can't draw and post pictures, so let me describe what I think you are trying to build. Then you can tell me where I have it wrong.
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- <font size="2" face="Verdana, Helvetica, sans-serif">You have one breaker (for which the trip rating is to be determined) supplying power to one branch circuit (for which the conductor size is to be determined).</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">This branch circuit supplies power to a "black box," with the brand name "GrafikEye" on the outside. I have no idea what this box is, nor what it does, nor what is inside it.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">From this box you have twelve wires going out (for which the size is to be determined). They all start off in the same conduit, and will branch off to separate loads somewhere downstream.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">One pair of wires (from this set of 12) supplies power to a LV transformer. Another pair supplies another LV transformer. In all, six LV transformers are supplied by the 12 wires.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">There is no separate overcurrent protection for the 12 wires. So they must be protected by the branch circuit breaker mentioned above.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">Therefore, the branch circuit wires to the "black box" and the 12 wires leaving that box must all be the same size, so that the one breaker can protect them all.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">The load on any one set of wires (i.e., any one LV transformer) is limited to 800 watts. If the load goes higher, something will burn up (I don't know if there is any internal protection against this happening).</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">The total load is limited (again, I don't know by what means) to 1920 watts. That is equivalent to 16 amps.</font>
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Now we start the design process.
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- <font size="2" face="Verdana, Helvetica, sans-serif">The ampacity of the 12 outgoing wires needs to be high enough to handle their load. That is 6.6 amps, as you have said.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">But the ampacity also has to be high enough to be protected by the selected breaker.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">The load seen by the branch circuit breaker is 16 amps, and is continuous. That requires us to use a breaker that is at least 125% of that load. A 20 amp breaker will do this job.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">Therefore, the conductors must have an ampacity of 20 amps or higher.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">The two branch circuit conductors are in a conduit by themselves, and therefore have no derating factor. You could use a #12 for this application, if there were no other consideration.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">But there is a 50% derating for the set of 12 outgoing conductors. In order to get a 20 amp ampacity, you need to use #10.</font>
<font size="2" face="Verdana, Helvetica, sans-serif">Is this the right configuration and the right design process? Do I have the "black box" all wrong? Are the LV transformers inside the "black box"? Are the 12 wires going someplace different than I have described?