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Derating:Experts Only

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svaurez

Member
Location
California
I dont understand derating.

If I have a 2" conduit with 3-3/0 conductors I don't have to derate.

If I have a 2" conduit with 6-#12 conductors I have to derate.

Whats the difference here?Why would the #12 wires generate more heat than the 3/0's?

[ March 14, 2004, 11:25 PM: Message edited by: svaurez ]
 

websparky

Senior Member
Location
Cleveland, Ohio
Re: Derating:Experts Only

Each conductor generates heat in proportion to the amont of current flow. Each conductor has an ampere rating based on it's size. If you imagine that all conductors are created equal and all conductors have the proper amount of current flow, then all conductors will generate an equal amount of heat. Heat defeats current flow. That said, the greater the number of conductors in a conduit, the greater the heat generated in the conduit and conversely the greater amount of resistance to current flow. This means the more conductors in a conduit, the less they are able to carry the usual amount of current. Therefore, when more than 3 current carrying conductors are in a conduit, their ability to carry full current is reduced.
 

peter

Senior Member
Location
San Diego
Re: Derating:Experts Only

Svaurez has a point. Perhaps someone could run the Neher-McGrath calculations for his two situations.
The beloved NEC is pseudo-scientific. Someone mentioned that most of the revenue of NFPA comes from sales of the NES. Sooner or later, someone will tkae advantage of the situation and produce a more co-herent, legible Code and put them out of business. The unproven AFCI requirement is a sell-out to a select few manufacturers, for instance. Would anyone miss the verbage devoted to the archaic two phase systems? [Perhaps send it all to an appendix for Philadelphia?]
~Peter
 

iwire

Moderator
Staff member
Location
Massachusetts
Re: Derating:Experts Only

I think it helps to think about it in extremes.

With only three current carrying conductors in a raceway or cable each conductor is exposed to the ambient temperature.

Now make it 20 current carrying conductors, many of these conductors will be surrounded by the other current carrying conductors.

The surrounded conductors can not dissipate the heat as well as those that are exposed to ambient temps.

Take a look at the differences from 310.16 to 310.17, the higher ampacitys in 310.17 are do to the conductors increased ability to dissipate the heat to the air. :)
 

svaurez

Member
Location
California
Re: Derating:Experts Only

If you think of a 3/0 conductor it is actually about 19 #12 conductors wrapped around each other.So three 3/0's in a 2" is actually about 60 #12 conductors.How does this situation dissipate heat easier than 6 #12's in a 2".
 

iwire

Moderator
Staff member
Location
Massachusetts
Re: Derating:Experts Only

svaurez I think that is a good question.

Here is what I think and maybe a engineer can let me know if I am on the right track.

I believe that the problem you bring up, a bigger conductors ability to dissipate heat is already figured in to the ampacity tables.

8 AWG copper is rated 40 @ 60 C it has an area of 16510 cir mils.

This works out to 413 cir mils per amp.

750 kcmil copper is rated 400 @ 60 C it has an area of 750,000 cir mils.

This works out to 1875 cir mils per amp.

It seems the larger the conductor the less capacity it has for a given area.

Just my wild guess, Bob
 

bob

Senior Member
Location
Alabama
Re: Derating:Experts Only

Bob
You make a good point. According to my Southwire Cable Manual, the AC/DC ratio for #8 is 1 while the AC/DC ratio for 750 is 1.29 in conduit.
This skin effect has a significant effect on the
ampacity of the cable. If I read this correctly it would seem that there is a reduction of useable
cir mill area for the 750 of 29%. Using your example this would equate to a area of 532500 cm. If you look at table 310.13 for thhn insulation you see that the insulation thickness for #8 is 30 mils while it is 70 mils for the 750. This is an increase of 233% added resistance to the thermal path for heat transfer and thus a reduced ampere capacity.

[ March 15, 2004, 12:28 AM: Message edited by: bob ]
 

iwire

Moderator
Staff member
Location
Massachusetts
Re: Derating:Experts Only

Originally posted by websparky:
Wow!
Somehow "Experts" are only allowed to post here!
I am going to break the 'rules' and post here anyway. :D

svaurez you will have to wait for an expert :D

You mentioned a 3/0 conductor.

Take a look at Table 8 and you find a 3/0 is 19 strands of 2.39 mm solid copper.

The closest solid copper conductor to that is a 12 AWG solid at 2.05 mm, a bit smaller than the strands of a 3/0.

310.16 rates the 12 solid 25 amps @ 60 C.

19 strands of 25 amp rated copper comes out to 475 amps.

The interesting thing is a 3/0 is rated 165 amps @ 60 C.

To me it is very clear the tables take into consideration that larger conductors can not carry as much current as smaller ones for a given amount of copper.

But I am no expert. :D

You asking questions on a free public forum, you do not get to pick and choose who responds :D
 

charlie b

Moderator
Staff member
Location
Lockport, IL
Occupation
Semi-Retired Electrical Engineer
Re: Derating:Experts Only

I nominate ?iwire? for an ?attaboy? on his responses. Let me elaborate.
Originally posted by iwire:The surrounded conductors can not dissipate the heat as well as those that are exposed to ambient temps.
That is the key to understanding the derating concept. But first a digression into background information.

Considered in isolation from the rest of the universe, the ability of a bare conductor to carry current is limited by its own cross-sectional area. Too much current will threaten the integrity of the metal structure, and will eventually lead to melting. Now you add insulation to the bare conductor. The heat generated from too much current will threaten the integrity of the insulation system long before the metal is in danger of melting. The better the insulation system, the more heat it can take (translate, ?the more current it can handle?), before there is a risk of failure. The ampacities shown in the 75C and 90C columns of Table 310.16 are higher than those of the 60C column for this very reason: the insulation system of a THW is better than that of a TW, and the insulation system of a THHW is better still.

So we limit the current to the values posted in 310.16 to protect the insulation systems. But 310.16 is based on a specific type of installation (?Not More Than Three Current-Carrying Conductors in Raceway, Cable, or Earth?) and on a specific limit on ambient temperature (30C). If you start at a higher ambient temperature, then you have less of a ?heat rise? to go before you exceed the insulation system?s temperature limit. But if instead of raising the temperature of the surrounding dirt, you add more current-carrying conductors, then each conductor will have to dissipate its heat in the presence of other conductors that are trying to do the same. None of them will have an easy time of it. From the perspective of each individual conductor, the ambient temperature surrounding it has risen, and that will cause its own temperature to rise.
Here is what I think and maybe a engineer can let me know if I am on the right track. I believe that . . . a bigger conductors ability to dissipate heat is already figured in to the ampacity tables.
I am not an expert, but I am an engineer. You are right. Before taking into account any derating factors, a 3/0 copper THHN is good for 225 amps, and a #12 copper THHN is good for 30 amps. If you put 3 of the 3/0 in one conduit, and three of the #12 in another conduit, then you could safely run every bit of the 225 amps through the first circuit, and every bit of the 30 amps through the second circuit, and you will not have to worry about the insulation systems of either circuit. (ASIDE: You also have to consider terminal provisions, but that?s another story.) Table 310.16 has already taken into account the greater ability of the larger conductor (and its larger insulation system) to carry current, when it assigned the 225 amp limit to the 3/0. If you now add a fourth current-carrying 3/0 to the first conduit, then each of the 3/0 conductors will see a higher ambient temperature that was assumed in the development of Table 310.16. That is why we can no longer pass every bit of the 225 amps through that circuit.
It seems the larger the conductor the less capacity it has for a given area.
That is because the current tends to travel along the outer edges of the conductor. This is the ?Skin Effect,? as ?the other Bob? has already correctly pointed out.
 

c-h

Member
Re: Derating:Experts Only

Best to put it up front: I'm no expert.

Bob #1 (not Iwire),

Could you find a reference that shows when the skin effect becomes an issue at the frequencies normally encountered (50/60Hz)? Would be very interesting. 750 kcmil is a very large conductor and I suspect that for sizes 500 kcmil and below the effect is small.

May I however respectfully disagree with your statement
...the insulation thickness for #8 is 30 mils while it is 70 mils for the 750. This is an increase of 233% added resistance to the thermal path for heat transfer and thus a reduced ampere capacity.
The thermal resistance includes the air around the wire and the thermal resistivity of air is higher than that of plastic. In some cases this leads to a very counterintuitive result: Adding more plastic insulation reduces the total thermal resistance. I haven't got the data to calculate if this is the case here, but I think you get the point.

Iwire (Bob #2)
I agree that the larger the conductor the less capacity it has for a given area, but I have a different explanation than Charlie. If it is wrong, the moderators are welcome to shout and throw me out.

Heat is generated in the conductors as R x I^2. This means that doubling the current quadruples the heat generated in the conductor. If you double the cross sectional area of the conductor, the resistance falls to half. This seems to indicate that doubling the area only increases the ampacity by the square root of 2, i.e. 1.41.

There is however one more thing to take into consideration, namely that doubling the cross sectional area increases the circumference, and hence the surface area, by the square root of 2. Assuming that the heat transfer from the conductor is directly proportional to the surface area, the amount of heat that leaves the conductor at a given temperature increases by the square root of 2.

All in all, doubling the cross sectional area has reduced the resistance to half and increased the heat dissipation by 1.41, yielding the result that the ampacity is square root of (1.41/0.5) = 1.68 of the ampacity of the conductor we started with. This doesn't quite agree with the actual ampacities listed in tables, but it is after all only a simplification.

[ March 15, 2004, 01:47 PM: Message edited by: c-h ]
 

dereckbc

Moderator
Staff member
Location
Plano, TX
Re: Derating:Experts Only

Originally posted by charlie b:
That is because the current tends to travel along the outer edges of the conductor. This is the ?Skin Effect has already correctly pointed out.
Can anybody point to a refference that there is skin effect at 60Hz and to what degree. I have worked a lot of AF and RF design, and the calculations I have used never included skin effect below 10Khz.
 

bennie

Esteemed Member
Re: Derating:Experts Only

I am not an expert either, but I did stay in a Holliday Inn last night.

c-h is correct; To add to his very good composition; first calculate the heat produced by components of the specific part of the circuit, then calculate the requirements for dissipating the heat.

Air is the lowest on thermal conductivity charts. With silver being the highest. Thermal conductivity is in line with electrical conductivity in various materials.

Heat is dissipated more readily from a conductor covered with plastic than a bare conductor in free air. The plastic acts as a heat sink. When the plastic is in contact with a metal conduit, the conduit acts as a heat sink for the plastic.

The temperature of a conductor at low levels, will not make a significant change in impedance.

The temperature of the insulation is the only factor to consider.
 

bob

Senior Member
Location
Alabama
Re: Derating:Experts Only

Southwire Cable Reference to skin effect is as follows for AC/DC resistance ratio:
3/0 - 1.02
4/0 - 1.03
250 - 1.04
300 - 1.05
350 - 1.07
400 - 1.09
500 - 1.14
750 - 1.29
1000 - 1.47
If I am not mistaken in the Neher McGrath caculations, the thermal resistance of the insulation is added to the thermal resistance of the air in the conduit plus the thermal resistance of the conduit to form the complete thermal path.
 
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