vincec
Member
- Location
- Woods Cross UT
- Occupation
- Engineer
I just watched one of Mike's listed video's "Available Fault Current Label". In the video Mike used the example of a 112.5 kva/208 v transformer, in his example with 3.2 % Z the fault current was close to 9,700 amps. Someone in the video brought up motor contribution and brought up changing out a motor with a 100 hp motor. The fault contribution of a motor is 5 X FLA, for a 100 amp motor it is 5 X 273, worse case would be 1365 amps. However this is impractical for a 112.5 kva transformer, 10 hp would be much more practical. 5 X FLA, for a 10 hp motor would be 5 X 30.8 = 154 amps. This would be 1.5 % of the utility contribution, and keep in mind that the motor contribution decays rapidly. I believe that Mike is right about leaving motor contribution out of the calculation of fault current, however it can be extremely important for calculating available fault current for internal customer equipment