Electrical Exam Prep Help?

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I assume this is what you are questioning. It is pretty straightforward but how one is expected to enforce this is another question

110.14(D) Installation. Where a tightening torque is indicated as a
numeric value on equipment or in installation instructions
provided by the manufacturer, a calibrated torque tool shall be
used to achieve the indicated torque value, unless the equipment
manufacturer has provided installation instructions for
an alternative method of achieving the required torque.
 
Preparing to take a Master Electrician Exam, just looking for some help along the way. I'll be posting questions as needed to get through the course, currently in Unit 6 - Conductor Sizing and Protection Calculations.


We are anxiously waiting
 
Feeder Sizing @ 90°C

Feeder Sizing @ 90°C

Page 249 Figure 6-16

If 300A continuous load @ 100% with 90°C wire on 90°C terminals is permitted, using the 90°C column for XHHW wire the first conductor size over 300A is 300kcmil at 320A. Why is the answer for this example 400 kcmil @380A? I thought I understood this concept in the 2017 NEC Handbook Section 215.2, but I can't get the right answers in any of the examples in the Exam Prep Book.

What am I missing?:?
 
300 x 125%= 380

The question seems to imply that the breaker is rated 100% but if that is not the case then 400 kcm is correct. The wording, to me, is a bit off.
 
I failed to mention the 400A breaker.

F6-16.JPG

The point of the example seems to be that 90° wire can be used at full 90° ampacity on 90° terminals permitting a smaller size for that segment. 125% full load doesn't apply to that 90° segment, but I completely missed that 300 kcmil XHHW (320A @ 90°C) would be enough for the load but undersized for the breaker.
 
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F6-71.jpg
I understand the neutral sizing starts with 100% continuous load, but how would I know to look to 220.61 and then conclude an unbalanced load of 100A based on what it says?
 
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