We are doing a lot of building here and we are commissioning a new 160ton chiller. There is only 277/480 at the pad and there was a 1000VA for three convenience outlets and a few lights. Well that 1000VA xfmr got overloaded and stopped so they replace it with a 3000VA xfmr. There is no secondary fusing and the engineer doesn't want it.
To me the old 1000VA xfmr was like a fusible link.
My view is that the 20A CB is protecting the little wire going in the xfmr but there should be a big wire leaving the xfmr. If not, there should be a fusible link.
The new 120v secondary can carry all the amps the 277v primary will supply. 277v @ 20A = 5540VA
5540VA / 120V = 46A
The devices and the wire are rated for 20A.
The distribution is split evenly left and right leaving the xfmr.
I say he needs two [2] 20A fuses, one to the left and one to the right.
How can I prove this?
Here's some fotos.
To me the old 1000VA xfmr was like a fusible link.
My view is that the 20A CB is protecting the little wire going in the xfmr but there should be a big wire leaving the xfmr. If not, there should be a fusible link.
The new 120v secondary can carry all the amps the 277v primary will supply. 277v @ 20A = 5540VA
5540VA / 120V = 46A
The devices and the wire are rated for 20A.
The distribution is split evenly left and right leaving the xfmr.
I say he needs two [2] 20A fuses, one to the left and one to the right.
How can I prove this?
Here's some fotos.