DimlyLit
Member
- Location
- Seattle, WA
- Occupation
- Electrician 4y
I have been racking my brain, what small part I have remaining after studying calculations, with the second part of the first load calculation example from Annex D.
There is a table showing the method of getting to the least unbalanced load of the neutral via the list of loads added to this structure for the second part of the example. After a lot of study, I think I understand all of it except the bottom row. The 3 amps, I assume, is the 25% motor load addition from NEC 430.24 derived from the 12 Amp AC unit as the largest motor load? But there is a 2 amp load shown on the lower right corner in the same row. I assume this is also a 25% load addition from the 8 amp disposal. But wasn't this 25% already taken with the 3 amp addition as the largest motor load? This adds amps to the phase line load and could potentially change the calculated load. Why was the 25% taken twice??
There is a table showing the method of getting to the least unbalanced load of the neutral via the list of loads added to this structure for the second part of the example. After a lot of study, I think I understand all of it except the bottom row. The 3 amps, I assume, is the 25% motor load addition from NEC 430.24 derived from the 12 Amp AC unit as the largest motor load? But there is a 2 amp load shown on the lower right corner in the same row. I assume this is also a 25% load addition from the 8 amp disposal. But wasn't this 25% already taken with the 3 amp addition as the largest motor load? This adds amps to the phase line load and could potentially change the calculated load. Why was the 25% taken twice??