- Location
- Chapel Hill, NC
- Occupation
- Retired Electrical Contractor
Can someone explain this? I don't understand the secondary on a motor and why it is used as it is in the calculation
(b) Two 30-hp, 460-V, 3-phase, wound-rotor motors, nameplate primary
full-load current 38 A, nameplate secondary full-load current 65 A,
40°C rise.
Conductor Ampacity
The full-load current value used to determine the minimum required conductor
ampacity is obtained from Table 430.250 [see 430.6(A)] for the
squirrel-cage motor and the primary of the wound-rotor motors. To obtain
the minimum required conductor ampacity, the full-load current is multiplied
by 1.25 [see 430.22 and 430.23(A)].
For the 25-hp motor,
34 A × 1.25 = 43 A
For the 30-horsepower motors,
40 A × 1.25 = 50 A
65 A × 1.25 = 81 A