Nope,
2-input Ex-OR Gate
Symbol Truth Table
B A Q
0 0 0
0 1 1
1 0 1
1 1 0
Boolean Expression Q = A ⊕ B Read as A OR B but NOT BOTH gives Q
Then, the logic function implemented by a 2-input Ex-OR is given as "either A OR B but NOT both" will give an output at Q. In general, an Ex-OR gate will give an output value of logic "1" ONLY when there are an ODD number of 1's on the inputs to the gate