Fault current-the other side

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gar

Senior Member
Location
Ann Arbor, Michigan
Occupation
EE
161102-2210 EDT

#2 copper at 20 C is 0.156 ohms. A loop of 2000 ft is 0.312 ohms. Multiply by 1.68 for aluminum and loop resistamce is 0.52 ohms. At 480 V RMS current is 480/0.52 = 920 A. Somewhat less if the wire is hotter. 900 A on a 30 A breaker would be instantaneous trip, about 8 mS.

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Cow

Senior Member
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Eastern Oregon
Occupation
Electrician
161102-2210 EDT

#2 copper at 20 C is 0.156 ohms. A loop of 2000 ft is 0.312 ohms. Multiply by 1.68 for aluminum and loop resistamce is 0.52 ohms. At 480 V RMS current is 480/0.52 = 920 A. Somewhat less if the wire is hotter. 900 A on a 30 A breaker would be instantaneous trip, about 8 mS.

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He mentioned aluminum gar. But you gave him the formula to follow regardless, I suppose.
 
Location
NE (9.06 miles @5.9 Degrees from Winged Horses)
Occupation
EC - retired
161102-2210 EDT

#2 copper at 20 C is 0.156 ohms. A loop of 2000 ft is 0.312 ohms. Multiply by 1.68 for aluminum and loop resistamce is 0.52 ohms. At 480 V RMS current is 480/0.52 = 920 A. Somewhat less if the wire is hotter. 900 A on a 30 A breaker would be instantaneous trip, about 8 mS.

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POCO sent me an updated FC of 740. L-L instead of L-N. Results @ 1000' AL is .008 seconds for a 30 amp FRS according to the curve. Not bad GAR, we might get the impression you know what you are doing, eventually.:D I have those resistances in my VD spreadsheet, all I had to do was think a bit.:dunce: It will be a simple add.

The fun part is adding the ROTO PHASE at this point and going another 900' of 4 AL. Ignoring it, we end up with about 157 Amps. 10 seconds for the 30 Amp Fuse.
 
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