Figuring Fahrenheit temperature.

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nizak

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I’m attempting to figure how much heat will be produced from a given amount of wattage.

Pertains to an electric pottery kiln

Any help appreciated.
 
At a minimum you need the thermal mass of the kiln and the thermal conductivity of the walls.

If you know how hot and how quickly it got there at one wattage (preferably a temperature vs time curve) you can extrapolate for other wattage

Jon
 
winnie said:
At a minimum you need the thermal mass of the kiln and the thermal conductivity of the walls.

If you know how hot and how quickly it got there at one wattage (preferably a temperature vs time curve) you can extrapolate for other wattage

Jon
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Thank you.
 
Careful! Heat is energy and watts are power. Not the same thing! Perhaps you mean heat gain for a given wattage. That calculation is easy. It's 3.411 BTUH/watt. Heat gain is BTU/hr or BTUH. Air conditioners are rated in BTUH, even though everyone says BTU's or tons. One ton = 12,000 BTU or the amount of heat required to melt 2,000 lbs of ice.

All of the watt-hours you put into an electric kiln become BTU's at the rate of 3.41 x P BTU/hr.
 
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JoeStillman said:
Careful! Heat is energy and watts are power. Not the same thing! Perhaps you mean heat gain for a given wattage. That calculation is easy. It's 3.411 BTUH/watt. Heat gain is BTU/hr or BTUH. Air conditioners are rated in BTUH, even though everyone says BTU's or tons. One ton = 12,000 BTU or the amount of heat required to melt 2,000 lbs of ice.

All of the watt-hours you put into an electric kiln become BTU's at the rate of 3.41 x P BTU/hr.
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The title of the thread suggests the OP wants to figure out a temperature of something at some distance from the kiln. Some clarification from the OP is requested.
 
gadfly56 said:
The title of the thread suggests the OP wants to figure out a temperature of something at some distance from the kiln. Some clarification from the OP is requested.
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It’s probably the same issue he asked about in the General forum. Operating a 240V kiln on 208V.

My guess is he’s trying to figure out the kiln performance with reduced input.

I agree, it’s very ambiguous.
 
4-20mA said:
Did not know that. That makes sense.

What's the time frame for the melt? I'm sure that's part of the equation.
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Time would be about power, but originally it was over 24 hours. Now the duration is 1 hour. So a 3-ton unit could remove 36,000 BTU/hr.
 
winnie said:
The heat to melt 1 ton of ice is given as 288,000 BTU.

Melt 1 ton of ice in 1 day and you get 1 'ton of cooling', thus 288000/24 = 12000 BTU per hour or 3517W
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Look at you, double-checking the math! Well done, well done.
 
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