jjs
Member
- Location
- Puryear, TN, USA
After reading through 5 pages of fire pump threads I could find on this forum, I still have a couple questions. I was able to get enough info to answer most of my questions, but I am posting my conclusions here so that someone can tell me if I made any mistakes based on what I learned from the forums and through reading the code. Thanks in advance.
I have a 208V, 3P 75HP fire pump. The utility was declared not reliable by the AHJ, so we have a NG genset for backup located outside.
The motor for the fire pump is a Baldor FPM2549T-2/4 SCI Ball Brg UL Listed, Class Insulation TYpe: Cls F Ins 40 Deg Amb 1.15 service factor http://www.baldor.com/mvc/DownloadCenter/Files/FL441
The nameplate FLA of the motor is 192.8 and LRA with ATL starter is 1170A. The NEC FLC is 211A. The NEC LRC for a 208V 75HP is 1200A.
The generator was sized based on using a Wye/Delta starter. The LRA for wye/delta should be ??????
The generator software provided a 230KW generator to supply the fire pump, which is the only load on the generator.
Normally this generator would get an 800A CB output. According to 2011 NEC 695.4(B)(2)(b) it seems i use 430.62 for sizing the CB for SC protection only. 430.62 refers to table 430.52 which sets the maximum rating for an inverse time breaker at 250% of FLC = 211*2.5 = 528A, so a 600A CB could be used. Is this correct?
What is the smallest CB that could be used? Is it 126% FLC? Assuming it actually starts the motor without tripping.
The feeders from the generator shall be sized based on 695.6(B)(2) which refers to 430.22 and VD requirements of 695.7 which requires no more than 15% voltage drop during starting and no more than 5% VD during running at 115% FLC
430.22 requires conductors be rated 125% of motor FLC = 264A which means 300 kcmil minimum.
For the 695.7(A) starting voltage drop calculations, if I plug in 1200A for LRC and 200’ of length, at 0.8PF I get 13.55%VD using 300KCMIL CU in RGS
For the 695.7(B) running voltage drop calculations, if I plug in 211A *1.15% for FLC and 200’ of length, at 0.8PF I get 2.74%VD using 300KCMIL CU in RGS
Fire Pump Controller can handle (1)#3-350MCM PER Ø
Feeder from utility transformer would also be 125% FLC so would also be 300kcmil. The generator and utility transformer are similar distances to the fire pump.
The utility requires a CT cabinet and meter for the fire pump. Do I size the CT cabinet on the 125% of FLC? Or LRC? Is there a direct code section I could cite for this?
Also, it is my understanding that the pressure maintenance pump (jockey pump) does not need to be backed up by the generator according to NFPA 20 4.25.8 “The pressure maintenance pump shall not be required to have secondary or standby power.” Any exceptions to this that would require me to put it on the generator?
The generator is located outside in a manufacturer’s enclosure. It is in a northern climate and requires some heaters and a battery charger. Do any of these auxiliary items need to be backed up by generator power?
Did I make any mistakes?
Thanks for your help.
JJS
I have not posted in a while, but I really appreciate the knowledge of all the people that answer.
I have a 208V, 3P 75HP fire pump. The utility was declared not reliable by the AHJ, so we have a NG genset for backup located outside.
The motor for the fire pump is a Baldor FPM2549T-2/4 SCI Ball Brg UL Listed, Class Insulation TYpe: Cls F Ins 40 Deg Amb 1.15 service factor http://www.baldor.com/mvc/DownloadCenter/Files/FL441
The nameplate FLA of the motor is 192.8 and LRA with ATL starter is 1170A. The NEC FLC is 211A. The NEC LRC for a 208V 75HP is 1200A.
The generator was sized based on using a Wye/Delta starter. The LRA for wye/delta should be ??????
The generator software provided a 230KW generator to supply the fire pump, which is the only load on the generator.
Normally this generator would get an 800A CB output. According to 2011 NEC 695.4(B)(2)(b) it seems i use 430.62 for sizing the CB for SC protection only. 430.62 refers to table 430.52 which sets the maximum rating for an inverse time breaker at 250% of FLC = 211*2.5 = 528A, so a 600A CB could be used. Is this correct?
What is the smallest CB that could be used? Is it 126% FLC? Assuming it actually starts the motor without tripping.
The feeders from the generator shall be sized based on 695.6(B)(2) which refers to 430.22 and VD requirements of 695.7 which requires no more than 15% voltage drop during starting and no more than 5% VD during running at 115% FLC
430.22 requires conductors be rated 125% of motor FLC = 264A which means 300 kcmil minimum.
For the 695.7(A) starting voltage drop calculations, if I plug in 1200A for LRC and 200’ of length, at 0.8PF I get 13.55%VD using 300KCMIL CU in RGS
For the 695.7(B) running voltage drop calculations, if I plug in 211A *1.15% for FLC and 200’ of length, at 0.8PF I get 2.74%VD using 300KCMIL CU in RGS
Fire Pump Controller can handle (1)#3-350MCM PER Ø
Feeder from utility transformer would also be 125% FLC so would also be 300kcmil. The generator and utility transformer are similar distances to the fire pump.
The utility requires a CT cabinet and meter for the fire pump. Do I size the CT cabinet on the 125% of FLC? Or LRC? Is there a direct code section I could cite for this?
Also, it is my understanding that the pressure maintenance pump (jockey pump) does not need to be backed up by the generator according to NFPA 20 4.25.8 “The pressure maintenance pump shall not be required to have secondary or standby power.” Any exceptions to this that would require me to put it on the generator?
The generator is located outside in a manufacturer’s enclosure. It is in a northern climate and requires some heaters and a battery charger. Do any of these auxiliary items need to be backed up by generator power?
Did I make any mistakes?
Thanks for your help.
JJS
I have not posted in a while, but I really appreciate the knowledge of all the people that answer.