Hi, please I need help to understand this question. here is:

- What is the full load current drawn by a 5hp, 208V 3phase motor?

Answer:

table 430.250 (15.2Amps x 1.10 = 16.72A)

I don't know where the

**1.10** came from, also table 430.250 for a 5ph/208V/3phase the F.L.C is 16.7 amps. I'm litter confused on this one. Please help. Thank you

I suspect that this was a test question that was first derived from an earlier NEC cycle, and not updated particularly well.

The 1987 NEC's Table 430-150 "Full Load Current - Three-Phase Alternating-Current Motors" had voltages of 115V, 230V, 460V, 575V, 2300V. The notes below the table instructed you that for 208V and 200V motors, increase the corresponding 230V motor full load current by 10% and 15%, repectively.

So for a 5HP motor, you'd get 15.2 FLA from the 230V column, and increase it by 10% to get the 208V FLA: 15.2A * 1.1 = 16.7A.

In 1990, Table 430-150 was updated to include columns for 200V and 208V, so you no longer had to apply the 10% or 15%. And of course, Table 430-150 (from '87 & '90) has become Table 430.250 in the more recent code cycles.

That's where the

**1.10** came from.