Werone
Member
- Location
- El Paso, Tx USA
The grounding electrical conductor sizing from the code book seems silly for solar installations.
Lets look at a 25 panel Enphase microinverter installation.
One panel, 60 cell poly, under fault conditions can output a maximum current about 1.072 times above its rated STC current at time 0, or when the short occurs. I am guessing that three 60 HZ cycles later the voltage drops to zero and the current is minimal, probably equivalent to the number of photons hitting the surface of the Silicon, since the voltage and the current are directly proportional then I expect the current to be miniscule. (All UL listed inverters have Ground Fault detection circuits.) Remember the panels would need to all have this ground fault at the same time.
The granularity of an enphase inverter system has 25 discrete inverter/panel systems that makes the probability of simultaneous failure very low, but even so, the 25 simultaneous DC ground faults would possibly output 200 amps for 3 cycles or .05 seconds after which the current would drop to near zero. Why do I need a GEC conductor sized at 8 AWG? Seperately derived systems usually have a generator or battery system that can output a much larger (100+ times) fault current than a solar system, and that is what this rule had in mind when it was conceived.
The fault current for many inverters does not go above its rating, a 8000 watt SMA (240 VAC) inverter for example has a fault current specification of 33.33 Amps, yet I am required to put in a 8 AWG wire for seperately derived systems. Remember that the nature of the PV panels to drop voltage and current after about 5 one hundredths of a second. The enphase microinverters output fault current is like one amp for three 60 HZ cycles.... it just seems that we are following a rule blindly or am I missing something? Why do I need an 8 AWG GEC from my inverters to the main panel?
Lets look at a 25 panel Enphase microinverter installation.
One panel, 60 cell poly, under fault conditions can output a maximum current about 1.072 times above its rated STC current at time 0, or when the short occurs. I am guessing that three 60 HZ cycles later the voltage drops to zero and the current is minimal, probably equivalent to the number of photons hitting the surface of the Silicon, since the voltage and the current are directly proportional then I expect the current to be miniscule. (All UL listed inverters have Ground Fault detection circuits.) Remember the panels would need to all have this ground fault at the same time.
The granularity of an enphase inverter system has 25 discrete inverter/panel systems that makes the probability of simultaneous failure very low, but even so, the 25 simultaneous DC ground faults would possibly output 200 amps for 3 cycles or .05 seconds after which the current would drop to near zero. Why do I need a GEC conductor sized at 8 AWG? Seperately derived systems usually have a generator or battery system that can output a much larger (100+ times) fault current than a solar system, and that is what this rule had in mind when it was conceived.
The fault current for many inverters does not go above its rating, a 8000 watt SMA (240 VAC) inverter for example has a fault current specification of 33.33 Amps, yet I am required to put in a 8 AWG wire for seperately derived systems. Remember that the nature of the PV panels to drop voltage and current after about 5 one hundredths of a second. The enphase microinverters output fault current is like one amp for three 60 HZ cycles.... it just seems that we are following a rule blindly or am I missing something? Why do I need an 8 AWG GEC from my inverters to the main panel?