GFCI for Motor

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Re: GFCI for Motor

A brown out will result in the trigger circuit not receiving enough energy to operate the breaker trip mechanism. Also, at some point, the applied voltage will be low enough that the solid state devices in the detection circuit connected to the output of the current transformer will move out of a useful location on their operating curves, effectively lobotomizing them. Which happens first will be a function of the particular manufacturer's assembly.

Simply put, the low voltages experienced during a brownout will decrease or defeat the successful operation of the ground fault detection of the device. Solid state devices tolerate this quite well.

The over voltage is another matter. As I think about it, it is probably a shrewd and deliberate circuit design that has given you the three expensive paperweights. Designing the circuit to fail at High Leg voltages to neutral is, in effect, an electronic rejection feature, helping to prevent misapplication of the breaker.
 
Re: GFCI for Motor

Yes, metelectric, your right the voltage is 208 and not 277 and I can't even blame it on a typing error.
Al, if the neutral connection is required on the line side as is stated does that mean if you loose the neutral that the ground fault sensing would be defeated and you would have no ground fault protection? The internal wiring that I show in my resourses indicate that the shunt trip is energized from the solid state cicuit powered by the current sensor only which infers that the circuit is not powered by L-N 120v. With a 2p GFCI which linwe would it be powered from? Loosing the wqrong line would defeat the GF. If I have an old GFCI around I'll take it appart to see.
Anyway, that's besides the point. The instuctions state that the pig tail must be connected to the neutral 2002NEC 110.3(B) Installation and Use. "Listed or labeled equipment shall be installed and used in accordance with any instructions included in the listing and labeling." So that neutral must be connected regardless.
 
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