I recentely used my hand held GFCI Tester on a GFCI protected ciruit. The tester showed satisfactory wiring but the circuit did not trip when the GFCI button was pressed on my tester. Back at the panel I pushed the test button located on the circuit breaker and it tripped.
Can someone tell me what is going on? Is the test button on the GFCI breaker a mechanical trip only or is an actual fault current created when the GFCI Breaker is pushed? Appreciate your response.
TVH
Simple enough, and the subject of several other threads here.
The built in test button uses a resistor to take a controller amount of current from the hot wire on the load side of the receptacle and feed it around the sensing transformer back to the neutral (or take a controller amount of current from the not on the line side of the transformer and feed it into the neutral on the load side.
Since it has access to both sides of the sensing coil (transformer) it can do this.
An external tester only has access to the load side of the sensor, so to create a current imbalance it has to send some current through the actual ground wire.
If there is no ground at the outlet, the plug-in tester cannot work.
The NEC allows the use of a three wire GFCI receptacle as a replacement for a two-wire receptacle with no ground feed to the box if a label is attached saying that there is no ground.
If the receptacle had a false ground, created by attaching its ground terminal to the neutral, the plug-in tester would not be able to detect that and the GFCI test button would just be sending current back down the neutral, which would not trip the breaker.