caosesvida
Senior Member
1. heat increases resistance of copper wire.
2. we derate wire 125% for continuous use.
3. If the resistance goes up the amperage goes down
at a given voltage.
Is the derating to keep the temperature down on the connections ie. 75 degree C.?
Is the resistance so small that it does not come into play in this situation.
I have amped out resistive heaters that were supposed to draw 90 amps at 240 volt, and found them drawing 100 amps when installed to #2 aluminum.When the proper wire was installed the amp draw went down and the excessive heat went away. At the time I thought that the heat was the culprit that increased the amp draw.
I*E=P
90a * 240v = 2160 watts.
R= E/I = 2.25 OHMS
If the resistance changes in the wire, that should cause a voltage drop ( wire in series with load), would not the amperage also go down? Would that also cause the watts/heat to go down also.
Or is it just that over time the heat buildup will degrage the insulation value?
I am prblbaly missing something very simple and elementary here, but its been buggin me for a while now, and this seems to be the place to get great answers. thanks for any help.
2. we derate wire 125% for continuous use.
3. If the resistance goes up the amperage goes down
at a given voltage.
Is the derating to keep the temperature down on the connections ie. 75 degree C.?
Is the resistance so small that it does not come into play in this situation.
I have amped out resistive heaters that were supposed to draw 90 amps at 240 volt, and found them drawing 100 amps when installed to #2 aluminum.When the proper wire was installed the amp draw went down and the excessive heat went away. At the time I thought that the heat was the culprit that increased the amp draw.
I*E=P
90a * 240v = 2160 watts.
R= E/I = 2.25 OHMS
If the resistance changes in the wire, that should cause a voltage drop ( wire in series with load), would not the amperage also go down? Would that also cause the watts/heat to go down also.
Or is it just that over time the heat buildup will degrage the insulation value?
I am prblbaly missing something very simple and elementary here, but its been buggin me for a while now, and this seems to be the place to get great answers. thanks for any help.