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surf more

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eastern NC
I have a 15kw nonlinear light load for a store,and a30 kw heat load.
15000 into120 v is 125amps
30000 multi 1.25 into 360 is 104 amps
Total of229amps for this conductora,b,cand n
Sorry bout typo on a phone
 

augie47

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Location
Tennessee
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State Electrical Inspector (Retired)
I have a 15kw nonlinear light load for a store,and a30 kw heat load.
15000 into120 v is 125amps
30000 multi 1.25 into 360 is 104 amps
Total of229amps for this conductora,b,cand n
Sorry bout typo on a phone

Sorry may be me but that doesn't not compute,,,,,

calculated load would be 15kw x 1.25 (continuous) for lighting or 18.75
30 kw for the heat for a total of 48.75

Hopefully the lighting could be balanced for a load of 198 amps per phase on a 240/120 system (obviously it would not be totally balanced)

Heat branch circuit would need to be 203 amps
Lighting branch circuits at 20 amps could be 1920 watts per circuit.
 
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augie47

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Location
Tennessee
Occupation
State Electrical Inspector (Retired)
o.k. store lights are normally figured continuous.
208 single phase ?
 

cadpoint

Senior Member
Location
Durham, NC
What about a H2O heater (even if a puppy/usually a unisex BR), and the receptical load ? ;)

If it's a barber or salon better add a washer and dryer (worst yet salon chairs)!
 

augie47

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Location
Tennessee
Occupation
State Electrical Inspector (Retired)
Voltage is 208/120
15kw load is single phase
30kw load is three phase
Guess I did overlook light situation with this problem
my error, I still have "reading"problems... I missed the "c" phase in your OP.

I'm unsure what you end goal is... real life or otherwise.
Taking your statement that the 15 kw is not continuous and assuming you can distribute that load evenly over all 3 phases, we simply have a 45 kw load at 208/120 3 phase. That you equate to 125 amps per phase.

You 30 kw branch circuit would be sized by Code at 104 amps (83 actual x 1.25)
and your lighting if non-continuous and if you wanted to keep it balanced would be spread over 9 circuits (load wise 6.25, but evenly divide that would take 9)

in the "unattainable" balanced condition your neutral current would be 0.
 
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