Alwayslearningelec
Senior Member
- Location
- NJ
- Occupation
- Estimator
So is either the connected or the demand KVA enough to size conductor or you need motor nameplate/schedule info?
I assume you would just convert the KVA to total volt-amps. So in the case of circuit #16 you'd take either the connected or demand KVA( not sure which) and it would be either 6,500 or 8,100 divided by 208v. Not sure if you have to then take that value and multiply by 125%.
I assume you would just convert the KVA to total volt-amps. So in the case of circuit #16 you'd take either the connected or demand KVA( not sure which) and it would be either 6,500 or 8,100 divided by 208v. Not sure if you have to then take that value and multiply by 125%.