bphgravity said:
Anyone want to try to prove me wrong???
That is easy. But it would require you to accept the notion that a "pull" is defined as a force tending to move an object in the direction of the entity that is creating the force, and that "push" is defined as a force tending to move an object in the direction opposite to the entity that is creating the force.
One of the earliest lesson in Physics class is drawing force diagrams. You show an object, and you draw arrows to depict the forces being imposed upon them. For example, if you consider a ball that you hold in your hand, there will be two arrows. One will point downwards, representing the force of gravity. The other will be upwards, representing the force imposed on the ball by your hand. If you hold your hand steady, then the two forces will be equal, and the ball will not move. This will be represented in the diagram by two equal (but opposite) arrows.
But if you were to let go of the ball, then there would be only once force, and you would represent it with only one (downwards) arrow. The force diagram will depict one external force, and will make clear that the object will move in the direction of that force.
Now draw a similar force diagram showing two magnets, lying on a table, with opposite poles facing each other. The drawing will show two objects, and two arrows. The two arrows will be in opposite directions. That is, the force imposed on the left-hand magnet will be towards the right, and the force imposed on the right-hand magnet will be towards the left. There are no other relevant forces, no other arrows.
Actually, you could also draw the same two arrows I mentioned above, relating to the hand holding the ball (i.e., gravity force downwards, force from table upwards). But since those two cancel each other out, I am calling them not relevant to this problem. I am also disregarding friction, but adding friction to the story does not alter its conclusion.
There is only one force on the left hand magnet, and it is to the right, and the magnet will therefore move to the right. Since the thing that is imposing the force on the left-hand magnet is located in the direction of motion of the left-hand magnet, that force is, by definition, a "pull." In addition, since there is no force originating to the left of the left hand magnet to compel it to move to the right, then one must conclude that there is no "push." I could say similar things about the force imposed on the right-hand magnet by the left-hand magnet.
Q.E.D.