Steelhead
Senior Member
- Location
- Southeastern Wisconsin
- Occupation
- Industrial Maint/Journeyman
Hi Guys,
I'm looking for some help in the interpertation of 210.19(A)(1) when looking at the noncontinous load and the continous load.
For example I have a dedicated circuit supplying a piece of equipment where the nameplate says the max load is 75A. I know for this particular application that the continous load is 50A, but occassionaly the load jumps to 60A for a short time. In sizing the minimum circuit ampacity my thoughts would be 50A continous x 1.25=62.5A therefore I could size the conductors for a minimum of 75A (4 AWG = 85A @ 75degrees C)based on the nameplate, but not needing to size the conductors at 125% of 75A because the continous load is 50A not 75A.
OR
would you figure out the ampacity as 50A continous x 1.25=62.5A plus 60A (short duration load) which would equal 122.5A (1 AWG = 130A @ 75 degrees C)? This method seems like overkill to me. Which method would be correct based on 210.19(A)(1)?
Thanks
I'm looking for some help in the interpertation of 210.19(A)(1) when looking at the noncontinous load and the continous load.
For example I have a dedicated circuit supplying a piece of equipment where the nameplate says the max load is 75A. I know for this particular application that the continous load is 50A, but occassionaly the load jumps to 60A for a short time. In sizing the minimum circuit ampacity my thoughts would be 50A continous x 1.25=62.5A therefore I could size the conductors for a minimum of 75A (4 AWG = 85A @ 75degrees C)based on the nameplate, but not needing to size the conductors at 125% of 75A because the continous load is 50A not 75A.
OR
would you figure out the ampacity as 50A continous x 1.25=62.5A plus 60A (short duration load) which would equal 122.5A (1 AWG = 130A @ 75 degrees C)? This method seems like overkill to me. Which method would be correct based on 210.19(A)(1)?
Thanks