Kratky07
Member
- Location
- Houston, TX
- Occupation
- Master Electrician- EC
Hey Gents,
I am designing an electrical service that will exclusively feed (2) 3PH 480V motors with VFDS. Here in Houston working with the local utility is a nightmare, and the larger the service size is the more ridiculous requirements are imposed by the utility providers making it very difficult to build out the services due to easements, based off thier poles/pad mount transformers needed to supply the customers load demand. That being said, I am trying to keep the service as small as possible to not have to have a huge pad mount transformer which is required once you exceed 1000 Amps I believe. So anything on my load calc over 800A means I need huge easement requirements with utiltiy basically making the customers install impossible.
Pump #1 name plate 480V3PH/400HP VFD INPUT CURRENT FLA-461 (Heavy Duty) the VFD spec sheet also reads 598.1A Normal Duty (no idea what that means exactly)
Pump#2 name plate 480V3PH/200HP VFD INPUT CURRENT FLA 243A (Heavy Duty) 315.3A (Normal Duty)
So for my load calc I selected the Normal Duty FLA on the VFD's spec sheet and my largest motor is 461Ax1.15%= 530A + my smaller pump 243A gives me 773A total. this works great because it keeps my customers service size at 800A, allowing us to build them an overhead service requiring no underground easement, allowing us to run underground conduits to each respective VFD in its desired location.
According to 430.128 I can size my disconnecting means to 115% and not 125% minimum or Max 175% with fusible disconnect per T430.52 which would make my service size massive.
Am I in the wrong for selecting the lower ampacity listed on the VFD (Heavy duty) vs Normal duty, and why is Normal duty so much higher of an input?
Also, My output currents are far lower than my inputs, but im assuming I need to use the input currents for my feeder/service size over output correct?
I dont work with VFD's much, so any input on this is super appreciated. THANKS!
I am designing an electrical service that will exclusively feed (2) 3PH 480V motors with VFDS. Here in Houston working with the local utility is a nightmare, and the larger the service size is the more ridiculous requirements are imposed by the utility providers making it very difficult to build out the services due to easements, based off thier poles/pad mount transformers needed to supply the customers load demand. That being said, I am trying to keep the service as small as possible to not have to have a huge pad mount transformer which is required once you exceed 1000 Amps I believe. So anything on my load calc over 800A means I need huge easement requirements with utiltiy basically making the customers install impossible.
Pump #1 name plate 480V3PH/400HP VFD INPUT CURRENT FLA-461 (Heavy Duty) the VFD spec sheet also reads 598.1A Normal Duty (no idea what that means exactly)
Pump#2 name plate 480V3PH/200HP VFD INPUT CURRENT FLA 243A (Heavy Duty) 315.3A (Normal Duty)
So for my load calc I selected the Normal Duty FLA on the VFD's spec sheet and my largest motor is 461Ax1.15%= 530A + my smaller pump 243A gives me 773A total. this works great because it keeps my customers service size at 800A, allowing us to build them an overhead service requiring no underground easement, allowing us to run underground conduits to each respective VFD in its desired location.
According to 430.128 I can size my disconnecting means to 115% and not 125% minimum or Max 175% with fusible disconnect per T430.52 which would make my service size massive.
Am I in the wrong for selecting the lower ampacity listed on the VFD (Heavy duty) vs Normal duty, and why is Normal duty so much higher of an input?
Also, My output currents are far lower than my inputs, but im assuming I need to use the input currents for my feeder/service size over output correct?
I dont work with VFD's much, so any input on this is super appreciated. THANKS!