Multiple motors, largest is intermittent though

[Finite10]

Several motors -fused with an inverse time delay breaker. The largest motor was also 5 minute intermittent duty cycle.

Not sure if I should take the largest motor at 125% as in 430.24 and ignored the 110% short-time duty percentage in Table 430.22(E), or what?

 

[ptonsparky]

Curious as to the size of the motors. Will the 15% difference be a make or break on the sale? I personally would size it at the 125%.

 

[Finite10]

Sorry should've been clear - this is for Master Exam and requires minimum size.
The largest was about 60hp and the others 20 and 30hp, so a significant difference in the one largest motor.

 

[cadpoint]

Sorry should've been clear - this is for Master Exam and requires minimum size.
The largest was about 60hp and the others 20 and 30hp, so a significant difference in the one largest motor.

So if you proof the equation of 430.24 which opens up an avenue to
430.22(E) where does this leave you?

Or is one of those funny words that vary in term usuage from MW:

?used in logic as a sentential connective that forms a complex sentence which is true when at least one of its constituent sentences is true

For grins, replace article(s) in for sentence above.

 

[Finite10]

Thank you. I looked at my field copy of the NEC and saw I'd highlighted 430.24 exception 1, and made a note by it. DOH! I even underlined the word 'or' in the title!

60hp, 3 phase, 240V, short time 5 minute-
430.24 exception 1 (last sentence) throws me right to Table 430.22(E);
FLC per Table 430.250 = 154A
Table 430.22(E) 154 @ 110% = 169.4A
Now-
Sum of all motors with the 169.4A value.

Is that right? I'm highlighting my clean exam copy now...