Look at the math. Assume 1000 amps, and 100 meters of feeder.
From table #9, the resistance of 2/0 is 0.3170 ohms per KM. That's 0.03170 ohms for our 100 meter feeder.
For 500 KCM, its 0.0845 ohms per KM. That's 0.00845 ohms for our 100 meter feeder.
For (2) sets of 500 KCM, and one set of 2/0, the total resistance of our feeder is:
[ (.03170 ^ -1 ) + (.00845 ^ -1) + (.00845 ^ -1)] ^ -1 = .003728 ohms.
The voltage dropped across our feeder at 1000 amps of load current is:
1000 amps * .003728 ohms = 3.728 volts.
Since that voltage is across each feeder, we can use it to find the current through each feeder. For the 2/0, the current is:
3.728 / .03170 = 118 amps.
For the 500's, the current is:
3.728/ .00845 = 441 amps (for each set of 500's).
Check our answer by adding the three currents and making sure we get our 1000 amp totol current:
118 + 441 + 441 = 1000 amps.
The smaller 2/0 wire does get the smaller current, but it is a lot smaller current than we would want.
The 500 KCM's each get 441 amps, but they are only rated at 380 amps. So they would be overloaded by 60 amps each. A significant amount.
Steve