I see that if I correctly apply 430.63 as instructed to do by 230.90 (A) Exception No 1 I would:
Add the sum of the other loads 13 amps to the rating permitted by 430.62
So 13 amps plus a 250 A device (250% times 52 FLC of largest motor is 150 amp device plus FLC of other motors in the group 108 amps is a 250 device per 430.62) yields a minimum rating of 263 amps.
If this is so and I have not made any errors, does this mean a 300 amp overcurrent protective device inverse time breaker is permitted to protect a set of 250 kcmil service entrance conductors?