Per Unit Values from a short circuit example

Grouch1980

Senior Member
Location
New York, NY
Gents,
I attached a one-line diagram that I'm looking at. It's from GE's white paper on short circuit calculations.

The 2nd attachment shows how they derive the per unit X and R values at each piece of equipment (transformers, motors, the cables, and the utility). The base power value throughout is 15000 kVA.

My questions are how they derived the X and R values where I highlighted in blue in the 2nd attachment.

For the utility (top blue rectangle): the equation to solve for the per unit impedance (Z)... shouldn't it be actual power / base power? The equation that they are using seems to be base power / actual power. The utility power is 1500 MVA. Base power as I mentioned above is 15000 KVA.

For Motor M1 (the bottom blue rectangle): what equation are they using to solve for the motor impedance X? The equation includes an X"d of 15% (sub-transient reactance) and a horsepower of 4000. I'm not familiar with the equation though. What equation is this?

Thanks!
 

Attachments

  • One-Line Diagram.jpg
    One-Line Diagram.jpg
    1.2 MB · Views: 11
  • R and X derivations.jpg
    R and X derivations.jpg
    1.4 MB · Views: 12
The utility X/R is a given or an assumption. The motor X calculation is putting the X value in per unit. X/R is given in the one-line. I think they are using the hp to approximate the kVA by the 0.8 in the divisor.
 
For the motor, they are getting current from horse power and then using the subtransient reactance% of 15/100.

For motors, to covert it to per unit, it is :

MPU = (HP / Sbase) * PF

They probably substituted that in.


X = X"d * (1 / Mpu )

X = X"d * ( Sbase / (HP * PF) )
 
I think they chose the base as 15,000 but I couldn't tell you why. You can try to calculate it with your own base and see if you get the same results.
 
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