perspective

[zooby]

"Therefore, 380 amps at 13,200 volts is equal to 10,450 amps at 480 volts". Would this be a a real world scenario or just how the math works out? I am trying to gain some insight as to what is actually "available" on our campus loop. Let me try to ask this way...... If all 22 xfmrs were 13,2 to 480V and all xfmrs were the same kVA and fused the same AND equal loads at each, would that 10,450 amps "be available" to divy up between them all?
I am sure there is a lot more to this crappy question than I realize but never know how one might learn something.

 

[jim dungar]

would that 10,450 amps "be available" to divy up between them all?

Not really. While it might work at 100% loading, that would be an outlier case.

Each transformer stands alone. You cannot take the unused capacity from one and apply to an overloaded one. So we don't normally talk total amps across different secondaries.
However your primary will see all of the load that is being drawn from the 22 individual transformers so discussing total amps at 13.2kV is valid.

 

[Tyler C]

Each transformer stands alone. You cannot take the unused capacity from one and apply to an overloaded one. So we don't normally talk total amps across different secondaries.

A way around this is if the transformers are paralleled, which then means there aren't different secondaries anymore, they are all one secondary.

If this is the case, you would also want the impedances of all 22 to match to ensure equal loading, which prevents fully loading one transformer before any other.

 

[zooby]

Thank you guys. I appreciate the time.