Danny89
Member
- Location
- Indian Land
Happy weekend fellas!
Want to make sure I got this right.
Situation...
3 inch emt 16 inches long from feeder distribution panel to troth.
Therefore no need for 310.15(b)(3)(a)
Reference chapter 9 table 1 note (4)
Now calculate 60% fill thhn wire for 3inch emt.
Chapter 9 table 4. Emt 3 in:
60% fill = mm2 (3421) , in2 (5.307)
Chapter 9 table 5. Thhn 12awg:
Mm2 (8.581), in2 (0.0133)
So...
3421÷8.581= 398.67...
398 wires 12 awg thhn can legally fit in 3 in emt that is 16 inch long because it is filled just below 60%.
I think that's right...
Thanks in advance!
Sent from my Moto Z (2) using Tapatalk
Want to make sure I got this right.
Situation...
3 inch emt 16 inches long from feeder distribution panel to troth.
Therefore no need for 310.15(b)(3)(a)
Reference chapter 9 table 1 note (4)
Now calculate 60% fill thhn wire for 3inch emt.
Chapter 9 table 4. Emt 3 in:
60% fill = mm2 (3421) , in2 (5.307)
Chapter 9 table 5. Thhn 12awg:
Mm2 (8.581), in2 (0.0133)
So...
3421÷8.581= 398.67...
398 wires 12 awg thhn can legally fit in 3 in emt that is 16 inch long because it is filled just below 60%.
I think that's right...
Thanks in advance!
Sent from my Moto Z (2) using Tapatalk