aaSpencer
Member
- Location
- south jersey
Thank you for the opportunity to post a question here. Please help me understand the NEC Article 220.84(A)(2):Each dwelling unit is equipped with electric cooking equipment.
Exception: When the calculated load for multifamily dwellings without electric cooking in Part III of this article exceeds that calculated under Part IV for the identical load plus electric cooking (based on 8 kW per unit), the lesser of the two loads shall be permitted to be used.
There is an existing building with 120/208 volts 3 phase 400 Amps that will be renovated into a (12) unit apartment. Electric water heater is 4.5 KW and combined gas PTAC is 3.8 KW for each unit.
If gas stove is installed, Table 220.84 is not applicable. and because of that, the calculated load will be around 154,600 KVA or 430 Amps.
If ‘exception’ (if allowed) is applied, 12*8000 = 96 KW is added, the total connected load now is at 250 KVA and at 0.41% demand factor, the feeder drops to 285 Amps.
And choosing the lesser of the two, clearly, the ‘exception’ will be used as permitted. So though, the electrical drawing will show as gas stove, the load calculation of 285 Amps can be applied to justify that the existing 400 Amps can be re-used.
Is that about right? Please advise on the best approach. Thank you in advance.
Exception: When the calculated load for multifamily dwellings without electric cooking in Part III of this article exceeds that calculated under Part IV for the identical load plus electric cooking (based on 8 kW per unit), the lesser of the two loads shall be permitted to be used.
There is an existing building with 120/208 volts 3 phase 400 Amps that will be renovated into a (12) unit apartment. Electric water heater is 4.5 KW and combined gas PTAC is 3.8 KW for each unit.
If gas stove is installed, Table 220.84 is not applicable. and because of that, the calculated load will be around 154,600 KVA or 430 Amps.
If ‘exception’ (if allowed) is applied, 12*8000 = 96 KW is added, the total connected load now is at 250 KVA and at 0.41% demand factor, the feeder drops to 285 Amps.
And choosing the lesser of the two, clearly, the ‘exception’ will be used as permitted. So though, the electrical drawing will show as gas stove, the load calculation of 285 Amps can be applied to justify that the existing 400 Amps can be re-used.
Is that about right? Please advise on the best approach. Thank you in advance.