That would be true if the efficiencies are equal.Both lights are new. i thought higher power factor would draw less amps for a given load ?
If the resistive part of the current (which lights the lamp) stays the same, then the magnitude (length) of the actual current vector must be greater. (The actual current will be the hypotenuse of a right triangle, whose length must always be greater than the length of either side.)I don't understand why a higher power factor would be less current draw. Isn't just the angle between voltage and current different?
I don't understand why a higher power factor would be less current draw. Isn't just the angle between voltage and current different?