Recently took a pre employment test. Had a question on one of the calculations. Question asked find branch circuit load for 1 counter mounted 6kw range and 2 wall mount ovens at 4 kw a piece. As per note 4 on 220.55 you can count them as one which is 14kw. Then in note 1 you increase column c 5 % for each kW over 12. So I added 10% to the 8 and multiplied 18% x the 14kw and came up with 2.52 then subtracted that factor from the 14kw and put 11.48kw as the branch circuit load. Am I right with this answer? Any help would be appreciated.
Pre employment calc ?
- Thread starter Chad304
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10% of 8kW is 0.8kW. 8kW+0.8kW=8.8kW. The demand load would be 8.8kW.
Im sorry in advance for sounding stupid but where does the first 6kw counter mount range come into play?
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To rephrase that for the OP, the value in column C is not a percentage, so you cannot take it as 8 percent and add ten percent to get 18%.
Instead you add ten percent of the value to the value, which is the same as multiplying by 1.10.
Instead you add ten percent of the value to the value, which is the same as multiplying by 1.10.
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