Hello all.
I'm providing power to sports lighting pole. The pole itself is compromised of 22 lights, each with a driver rated at 480V, 2.75A, 1320W single phase. I plan on running 3 phase 480V to the pole and balance the 3 phase hot runs into 22 fixtures. So each fixture will take two hot wires.
Now if we take the required circuit breaker at the panel for the feeder i end up with 1,320W X 22 = 29,0470W === 34.94 A FLA x 1.25 continuous load = 43.6A Amps so next breaker size would be 3 pole 45A.
If i do phase to phase (I Line) per IL=(I1^2+I2^2+(I1×I2))^.5 for all the individual fixtures then i end up with, since we dont have even fixtures on each phase:
The fixture driver is EPH-LS-16-1200L (HV Driver).
Thank you,
I'm providing power to sports lighting pole. The pole itself is compromised of 22 lights, each with a driver rated at 480V, 2.75A, 1320W single phase. I plan on running 3 phase 480V to the pole and balance the 3 phase hot runs into 22 fixtures. So each fixture will take two hot wires.
Now if we take the required circuit breaker at the panel for the feeder i end up with 1,320W X 22 = 29,0470W === 34.94 A FLA x 1.25 continuous load = 43.6A Amps so next breaker size would be 3 pole 45A.
If i do phase to phase (I Line) per IL=(I1^2+I2^2+(I1×I2))^.5 for all the individual fixtures then i end up with, since we dont have even fixtures on each phase:
- Circuit AB (7 fixtures): 7×2.75A=19.25A ------ IA≈35.72A x 1.25 = 44.65A
- Circuit BC (7 fixtures): 7×2.75A=19.25A ------ IB≈33.34A x1.25
- Circuit CA (8 fixtures): 8×2.75A=22.00A ------ IC≈35.72A x 1.25 = 44.65A
The fixture driver is EPH-LS-16-1200L (HV Driver).
Thank you,