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pinman10

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suppose you have two 6 kw and one 8 kw ovens how would you find the demand load for this branch circuit thanks
 
ok i'm looking at table 250.55 note 3 says add them up and multiply by demand factors in table b in this case.i add the 3 oven kilowatts up and get 20kw then look under column b for number of appliances wich is 3 and go across to 55.so would it be 20kw times 55 %.0r 11 kw load demand.i'm not sure if thats right
 
pinman10 said:
ok i'm looking at table 250.55 note 3 says add them up and multiply by demand factors in table b in this case.i add the 3 oven kilowatts up and get 20kw then look under column b for number of appliances wich is 3 and go across to 55.so would it be 20kw times 55 %.0r 11 kw load demand.i'm not sure if thats right
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So it's in a dwelling then?
 
You have it. Use the percentage in column B. You may also use the value in Column C if you are not comfortable with the value in column B, which would be 14KW. This would be for the service or feeder load. Each of the ovens will need to be installed on it's own branch circuit (or tap conductor) sized in accordance with 220.19(3).
 
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