Range calc query...

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garykay

New member
:confused: I teach first year electrical and have a quiz question I now have 5 separate answers for and would like a few more, preferably a correct one with the logic backing it up.
9 apartment units all with ranges (this is a load calc) 3 units with 18kw ranges, 3 units with 8kw ranges and 3 units with 3kw ranges.
My first thought was to use columns A, B and C for each of the 3 corresponding sets and add the sum of the 3 answers. Having spoke with coworkers it was suggested that note 2, ranges of unequal rating, be applied and "...using 12kw for any range less than 12kw..." but the ranges of 8 kw and 3 kw do not fit into the parameters of note 2. (Some being less than 8 3/4kw) Further it was suggested to use both notes 2 and 3 and combine these sums when calculated (breaking the problem into parts). It was also suggested to add all of the items together for a total kw and divide by the 9 appliances to find the "average" and then apply note 2.
...OR... am I simply reading way to much into this considering 220.84 C multifamily dwellings, (we dont do multifamily from our shop).
 

haskindm

Senior Member
Location
Maryland
Use the optional calculation and figure all of the ranges at nameplate!
Seriously I believe you MAY use either method. Using colums A, B, and C for the appropriate ranges and then add the results together or use note 3 for the smaller ranges and then add the ranges from column C.
 

cpal

Senior Member
Location
MA
3-18kW from Col C = 14 +25% (18-12=5 *5%) = 17.5 Note 2
3- 8kW *3=24 * .55 from col B = 13.2 Note 3
3- 3kW *3= 9 *.7 from col A = 6.3 Note 3

total load =37kW?????
 
garykay,
Your first thoughts are correct. The 3 and 8 kW ranges do not meet the parameters of Note 2 under Table 220.55.

Start with the 18 kW ranges and apply Note 1. Select the kW demand for three ranges in Column C. (14 kW) Because the ranges are 6 kW more than 12 kW, multiply 6 by 5%. (6 x 0.05 = 0.30) Increase the demand for three ranges in Column C by 30%. (14 x 0.30 = 4.2 + 14 = 18.2) The demand for three 18 kW ranges is 18.2 kW.

Next multiply the 8 kW ranges by the demand factor percent for three ranges in Column B. (3 x 8 x 55% = 13.2) The demand for the three 8 kW ranges is 13.2 kW.

Now multiply the 3 kW ranges by the demand factor percent for three ranges in Column A. (3 x 3 x 70% = 6.3) The demand for the three 3 kW ranges is 6.3 kW.

Finally, total the demand for all three columns. (18.2 + 13.2 + 6.3 = 37.7 kW) The total demand is 37.7 kW.

Charles
 
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